1 / 39

Lesson 13.3 Similar Right Triangles pp. 548-553

Lesson 13.3 Similar Right Triangles pp. 548-553. Objectives: 1. To prove that the altitude to the hypotenuse of a right triangle divides it into two right triangles, each similar to the original. 2. To define and apply geometric means.

Download Presentation

Lesson 13.3 Similar Right Triangles pp. 548-553

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Lesson 13.3 Similar Right Triangles pp. 548-553

  2. Objectives: 1. To prove that the altitude to the hypotenuse of a right triangle divides it into two right triangles, each similar to the original. 2. To define and apply geometric means. 3. To compute lengths of sides and related segments for right triangles by using proportions.

  3. Theorem 13.4 An altitude drawn from the right angle to the hypotenuse of a right triangle separates the original triangle into two similar triangles, each of which is similar to the original triangle.

  4. A D B C ADB ~ BDC ADB ~ ABC BDC ~ ABC

  5. In the proportion , notice that the denominator of one ratio is the same as the numerator of the other ratio. When this happens, x is called the geometric mean. a x = x b

  6. 16 8 . = 8 4 For example, 8 is the geometric mean between 16 and 4 because

  7. 3 x = x 27 EXAMPLE 1 Find the geometric mean between 3 and 27. x2 = 81 x =  81 x = 9

  8. 6 x = x 9 EXAMPLE 2 Find the geometric mean between 6 and 9. x2 = 54 x =  54 x = 3 6

  9. 5 x = x 25 x = ± 125 x = 5 5 Practice: Find the geometric mean between 5 and 25. x2 = 125 ≈ 11.2

  10. Practice: Find the geometric mean between 12 and 20.

  11. Theorem 13.5 In a right triangle, the altitude to the hypotenuse cuts the hypotenuse into two segments. The length of the altitude is the geometric mean between the lengths of the two segments of the hypotenuse.

  12. D x A a B b C a x AB DB = , or = x b DB BC

  13. Theorem 13.6 In a right triangle, the altitude to the hypotenuse divides the hypotenuse into two segments such that the length of a leg is the geometric mean between the hypotenuse and the segment of the hypotenuse adjacent to the leg.

  14. D A B C AB BC AD DC = = AD DC AC AC

  15. 4 x H 4 = x 16 16 y x I z J EXAMPLE 3Given the measurements in HIJ, find x, y, and z. x2 = 64 x = 8

  16. 4 y H 4 = y 20 16 y x I z J EXAMPLE 3Given the measurements in HIJ, find x, y, and z. y2 = 80 y = 4 5

  17. 16 z H 4 = z 20 16 y x I z J EXAMPLE 3Given the measurements in HIJ, find x, y, and z. z2 = 320 z = 8 5

  18. Practice: Given: Right JKL with altitude to the hypotenuse, MK; LJ = 20, and MJ = 4, find KM. K J M L

  19. Practice: Given: Right JKL with altitude to the hypotenuse, MK; MJ = 4, and KJ = 6, find LJ. K J M L

  20. Homework pp. 552-553

  21. ►A. Exercises Solve each proportion; assume that x is positive. 3. x 4 = 9 x

  22. ►A. Exercises Solve each proportion; assume that x is positive. 5. x – 3 2 = 2 x

  23. ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 7. AD = 15 units; DB = 5 units; find AC C A D B

  24. ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 9. AB = 32 units; DB = 6 units; find CD C A D B

  25. ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 11. AD = 6 units; AB = 10 units; find CD C A D B

  26. ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 13. AD = 11 units; DB = 5 units; find AC C A D B

  27. ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 15. AD = 12 units; AB = 18 units; find CB C A D B

  28. ■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 23. Two circles with radii 3 and 6

  29. ■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 24. Two rectangles: 6 by 9 and 8 by 12.

  30. ■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 25. Two rectangles: 6 by 8 and 16 by 18.

  31. ■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 26. Two regular tetrahedra with sides of length 9 and 6 respectively

  32. ■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 27. Two squares with sides of length s and t respectively.

  33. Analytic Geometry Slopes of Perpendicular Lines

  34. Theorem If two distinct nonvertical lines are perpendicular, then their slopes are negative reciprocals.

  35. Z(x2, y1) X(x1, 0) Y(x3, 0) W(x2, 0) l1 l2

  36. ►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 1. y = -4/3x + 5 with y-intercept (0, -8)

  37. ►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 2. y = 2x – 1 and passing through (1, 4)

  38. ►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 3. the line containing (2, 5) and (3, 4) at the first point.

  39. ►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 4. y = 1/2x + 5, if their point of intersection occurs when x = 2

More Related