130 likes | 227 Views
Machine Learning Paper Reading Series. Distances between Data Sets Based on Summary Statistics. Nikolaj Tatti, JMLR, 01/2007. Presented by Yuting Qi ECE Dept. Duke Univ. 02/02/2007. Introduction. Goal:
E N D
Machine Learning Paper Reading Series Distances between Data Sets Based on Summary Statistics Nikolaj Tatti, JMLR, 01/2007 Presented by Yuting Qi ECE Dept. Duke Univ. 02/02/2007
Introduction • Goal: • Define a dissimilarity measure, the constrained minimum (CM) distance, between two data sets D1 and D2 by comparing summary statistics of datasets. • Requirements: • It should be a metric. • It should consider the statistical nature of data. • It should be evaluated quickly.
The Constrained Minimum (CM) Distance 1/5 • Definition: • Basic notations: • D: data set, a finite collection of samples in Ω. • Ω: finite sample space, |Ω| is the # of elements in Ω. • S: feature function, , known or learned. • Θ: frequency, , the average values of S over D, S(D) Example: Ω={A,B,C}, D1=(C,C,C,A), D2=(C,A,B,A) The only feature of interest is the proportion of C in the data set, then the feature function S is S(D1)=3/4, S(D2)=1/4
Given θ1 and θ2, // The Constrained Minimum (CM) Distance 2/5 • Constrained set of distributions: • An alternative definition of : • Constrained space: P is the set of all distributions defined on Ω. Calculated from given data sets We estimate statistics from given data set, then examine the distributions that can produce such statistics. If think Ω={1,2,…,|Ω|}, Pis a set of vectors, u, in R|Ω| satisfying non-negative elements and summing to 1. ui=p(i)
The Constrained Minimum (CM) Distance 3/5 • Illustration: Example: Ω={A,B,C}, D1=(C,C,C,A), D2=(C,A,B,A) the feature function S is S(D1)=0.75, S(D2)=0.25 P is the triangle, is a plane Then, C(S, 0.75), C(S, 0.25) are parallel lines The constrained set of distributions C+(S, 0.75), C+(S, 0.25) are the segments Motivate: A nature way to measure the distance between two parallel spaces: find the shortest length from two points from each space. C B A
The Constrained Minimum (CM) Distance 4/5 • CM Distance • Pick a vector from each constrained space • CM distance between D1 and D2 is • Theorem 1 • Computation time: • |Ω| could be very large, O(N3) time is feasible
The Constrained Minimum (CM) Distance 5/5 • Properties:
CM Distance and Binary Data Sets 1/2 • Basic definitions: • Sample space: • Itemset: , ai corresponds to ith dimension. • Boolean formula S: Ω->{0,1} • Conjunction function SB: • SB(w)=wi1^wi2^…^wiL, given itemset B={ai1, …, aiL} • Parity function TB: • TB(w)=wi1+wi2+…+wiL (+: XOR) • Given a collection of itemsets F={B1,…, BN}, we have
CM Distance and Binary Data Sets 2/2 • CM distance can be calculated in O(N) time assuming know θ1 and θ2.
CM Distance and Event Sequences 1/1 • Transform a sequence s to a binary data set Given a window length k, pick a window in s and transform it into a binary vector of length |Ω| (the alphabet) by setting 1 if the corresponding symbol occurs in window. S->D • Define a way F to represent the statistics of sequence s, popular choice is episodes. • Given transformed data sets D1, D2, F, the CM distance between s1 and s2 is
Empirical Tests • 7 datasets: • Bible, Addresses, Beatles, 20Newsgroups, TopGenres, TopDecades, Abstact • Compare CM distance to a base distance • Clustering experiments using different algorithms based on CM distance.
Conclusions & Discussion • CM distance has nice statistical properties and can be evaluated efficiently • It takes properly into account the correlation between features • For many types of feature functions, the computation time of CM distance is fast. • The performance of CM distance depends heavily on the data set.