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> –2. p 3. p 3. p 3. (3) > –2 (3) Multiply each side by 3. p > –6 Simplify. COURSE 3 LESSON 2-7. Solving Inequalities by Multiplying or Dividing. Solve > –2. Graph the solution. 2-7. >. >. >. >. –. –. –. –. Words number of CDs • $12 is at least $84,000.
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> –2 p 3 p 3 p 3 (3) > –2(3)Multiply each side by 3. p > –6 Simplify. COURSE 3 LESSON 2-7 Solving Inequalities by Multiplying or Dividing Solve > –2. Graph the solution. 2-7
> > > > – – – – Words number of CDs • $12 is at least $84,000 Let c = the number of CDs. Inequality c • 12 84,000 12c 84,000 12c 12 84,000 12 Divide each side by 12. c 7,000 Simplify. COURSE 3 LESSON 2-7 Solving Inequalities by Multiplying or Dividing A small business sells each CD of its game software for $12. How many CDs must they sell to meet the goal of at least $84,000? 2-7
COURSE 3 LESSON 2-7 Solving Inequalities by Multiplying or Dividing (continued) The business must sell at least 7,000 CDs. Check for Reasonableness The answer makes sense because 7,000 • 12 is 84,000, and any number over 7,000 multiplied by 12 is a number greater than 84,000. 2-7