520 likes | 988 Views
Acid-Base Equilibria: Acids and Bases What makes an Acid an Acid? An acid possess a sour taste An acid dissolves active metals magnesium An acid causes certain vegetable dyes to turn characteristic colors What makes a Base a Base? A bases possess a bitter taste
E N D
Acid-Base Equilibria: Acids and Bases • What makes an Acid an Acid? • An acid possess a sour taste • An acid dissolves active metals magnesium • An acid causes certain vegetable dyes to turn characteristic colors • What makes a Base a Base? • A bases possess a bitter taste • A base feels slippery to the touch • A base causes certain vegetable dues to turn a characteristic color
7 strong acids and 8 strong bases • Acids - HI, HBr, HCl, HClO3, HClO4, H2SO4, HNO3 • Bases – LiOH, NaOH, KOH, RbOH, CsOH, Ca(OH)2, Sr(OH)2, Ba(OH)2
The Arrhenius Definition of an Acid and a Base An acid is a substance that produces H+ ions in water solutions HCl H+ + Cl- A base is a substance that produces OH- ions in a water solution NaOH Na+ + OH-
acid dissociation equations HC6H5O3 C6H5O31- + H+ Fe(H2O)63+ Fe(H2O)5(OH)2+ + H+ CH3CH2NH31+ CH3CH2NH2 + H+
The Proton in Water When HCl dissolves in water we write: HCl(g) H+(aq) + Cl-(aq)
Reality for the Hydronium ion H5O2+ H9O4+
Acidic solutions are formed by a chemical reaction in whichand acid transfers a proton (H+) to water, so we can write them either way. HCl(aq) + H2O(aq) H3O+(aq) + Cl-(aq) or HCl(aq) H+(aq) + Cl-(aq)
Nitrogen compounds are Bronsted acids when they are protonated. NH4Cl NH4+ NH3 + H+ CH3)2NH2+ (CH3)2NH + H+
The Bronsted-Lowry definition for Acids and Bases Acids may be defined as a substance that is capable of donating protons Bases may be defined as substance that accepts protons. HCl + NH3 NH4++Cl- acid base conjugate conjugate acid base
Is Water an Acid? NH3(aq) +H2O(aq) NH4+(aq) + OH-(aq)
Is Water a Base? HC2H3O2(aq) + H2O(aq) H3O+(aq) +C2H3O21-(aq)
+ H H H .. : : : H H O O .. O + O : : + : H H H The auto ionization of water The reaction occurs to a very small extent; about 1 in 108 molecules is ionized at any given moment
Dissociation of Water, pH Scale H2O(l) H+(aq) + OH-(aq) K =[H+] [OH-] [H2O] since water is a liquid and its concentration is therefore constant, this expression may be written as: Kw = [H+] [OH-] = 1.0 x 10-14 [H+] = [OH-] = 1.0 x 10-7 M
Sample exercise: Indicate whether each of the following solutions is neutral, acidic, or basic: • [H+] = 2 x 10-5 M • [OH-] = 0.010 M • [OH-] = 1.0 x 10-7 M
Calculate the concentration of H+(aq) in • a solution in which the [OH-] is 0.020M • a solution in which the [OH-] = 2.5 x 10-6 M. Indicate whether the solution is acidic or basic
The pH Scale pH = -log [H+] If [H+] = 2. 5 x 105 the pH is? pH = -log [2. 5 x 10-5 ] = 4.6 If pH is 3.8 the H+ concentration is Antilog -3.8= 1.58 x 10-4 M
In a sample of lemon juice, [H+] = 3.8 x 10-4 M. What is the pH? A commonly available window cleaner has a [H+] = 5.3 x 10-9 M. What is the pH? In a sample of freshly pressed apple juice has a pH of 3.76. Calculate the [H+]
What if we took the –log of the Kw expression Kw = [H+] [OH-] = 1.0 x 10-14 pKw = pH + pOH = 14
What is the pH, [H+], [OH-], of a solution with a pOH of 2.5? Is the solution acidic or basic?
Major species HCl(aq) + H2O(aq) H3O+(aq) + Cl-(aq) or HCl(aq) H+(aq) + Cl-(aq) HC2H3O2(aq) + H2O(aq) H3O+(aq) +C2H3O21-(aq) Pb(NO3)2 + NaCl →NaNO3 +PbCl2
What is the pH of 0.010 M solution of HCl? If it ionizes completely which is what strong means then take the negative log of the concentration. HCl(aq) H+(aq) + Cl-(aq) .01M .01M .01M pH = 2
What is the pH of a solution made from 20mL of 2.0M HCl and 35mL of 3.2M HNO3?
What about H2SO4 H2SO4 → H+ + HSO41- (Strong) HSO41- → H+ + SO42- (Weak)
What about weak acids HX(aq) H+(aq) + X-(aq), then Ka = [H+][X-] [HX] The smaller the value of the acid dissociation constant Ka, the weaker the acid
What is the Ka of a 0.10 M solution of formic acid (HCHO2) which has a pH = 2.38? HCHO2 H+ + CHO21- I 0.10 0 0 C .00417 .00417 .00417 E .0958 .00417 .00417 Ka = (.00417)2 = 1.8 x 10-4 .0958
What is the concentration of H+ ions in a 0.10 M solution of HC2H3O2 (Ka = 1.8 x 10-5)? pH? % ionization? HC2H3O2 H+ + C2H3O21- I .10 0 0 C -X +X +X E .10 – X X X 1.8 x 10-5 = X2 X = 1.3 x 10-3 .10 – X pH = 2.87
percent dissociation 1.3 X 10-3 x 100 = 1.3% .10
What is the pH and percent ionization of a 0.20 M solution of HCN? Ka = 4.9 x 10-10
Acid-Base Equilibria: Strong Bases The most common soluble strong Bases are the hydroxides of group IA and Ca, Ba and Sr What is the pH of a 0.010 M solution of Ba(OH)2?
Amines Anions of Weak Acids
Dealing with Weak Bases The base dissociation constant Kb refers to the equilibrium in which a base reacts with H2O to form the conjugate acid and OH- Weak base + H2O conjugate acid + OH- NH3(aq) + H2O (l) NH4 +(aq) + OH-(aq) [NH4+][OH-] Kb = [NH3] Calculate the [OH-] in a 0.15 M solution of NH3. NH3 + H2O NH4+ + OH- I C E
Polyprotic Acids H2SO3(aq) H+(aq) + HSO3-(aq) Ka1 = 1.7 x 10-2 HSO3-(aq) H+(aq) + SO32-(aq) Ka2 = 6.4 x 10-8 Calculate the pH of a .1M solution
Anions of Weak Acids HC2H3O2(aq) + H2O(aq) H3O+(aq) + C2H3O2-(aq) Bronsted acid Bronsted base Conjugate acid Conjugate base A second class of weak base is composed of the anions of weak acids Anions of weak acids can be incorporated into salts. NaC2H3O2 Na+(aq) + C2H3O2-(aq) C2H3O2- + H2O HC2H3O2 + OH- Kb = 5.6 x 1010
NaOH(aq)+HC2H3O2(aq→H2O+NaC2H3O2 NaC2H3O2 Na+(aq) + C2H3O2-(aq) Na+(aq) + H2O ← NaOH(aq) + H+(aq) C2H3O2-(aq)+H2O HC2H3O2 (aq)+OH- (aq)
NH4Cl → NH4+ + Cl- NH4+ NH3 + H+
NH4Cl NaC2H3O2 NH4C2H3O2
Anions of Weak Acids Calculate the pH of a 0.01 M solution of sodium hypochlorite (NaClO) ClO- + H2O HClO + OH- I C E
Now it’s you turn: the Kb for BrO- is 5.0 x 10-6. Calculate the pH of a 0.050 M solution of NaBrO
Ka and Kb NH3(aq)+ H2O NH4+ (aq)+ OH-(aq) NH4+(aq) NH3(aq)+ H+(aq) [NH4][OH- ] [H+][NH3] Ka = Kb = [NH4+] [NH3] NH4+(aq) NH3(aq) + H+ (aq) NH3(aq) + H2O(l) NH4+(aq) + OH- (aq) H2O H+(aq) + OH-(aq) When two reactions are added to give a third reaction, the equilibrium constant for the third reaction reaction is given by the product of the equilibrium constants for the two added reactions pKa + pKb = pKw Ka x Kb = Kw
Calculate the (a) base-dissociation constant, Kb, for the fluoride ion, is the pKa of HF = 3.17 pKa = -log Ka 3.17 = -log Ka Antilog -3.17 = 6.76 x 10-4 Since Ka x Kb = Kw (6.76 x 10-4)x Kb = 1.0 x 10-14 Kb = 1.0 x 10-14/ 6.76 x 10-4 = 1.5 x 10-11
Calculate the pKb for carbonic acid (Ka = 4.3 x 10-7) Now it’s your turn
Acid-Base Properties of Salt Solutions • Anions of weak acids, HX, are basic and will react with • H2O to produce OH- X- (aq) + H2O (l) HX(aq) + OH-(aq) • Anions of strong acids, such as NO3-, exhibit no basicitiy, • these ions do not react with water and consequently do not • influence the pH • Anions of polyprotic acids, such as HCO3-, that still have ionizable protons are capable of acting as either proton donors or acceptors depending upon the magnitudes of the Ka or Kb
Anions of polyprotic acids, such as HCO3-, that still have ionizable protons are capable of acting as either proton donors or acceptors depending upon the magnitudes of the Ka or Kb Predict whether the salt Na2HPO4 will form an acidic or basic solution on dissolvingin water. Na2HPO4 2Na+ (aq) + HPO4- HPO4- acting like an acid K3 = 4.2 x 10-13 HPO4-(aq) + H2O H3O+ + PO43-(aq) HPO4- acting like an base 1.0 x 10-14 HPO4- (aq) + H2O H2PO42-(aq) + OH-(aq) Kw = Kb = 6.2 x 10-8 Ka So HPO- is the conjugate base of H2PO4-. Since the K2 of H2PO4- = 6.2 x 10-8 then: 1.6 x 10-7 = Since Kb is larger than Ka, HPO4- will act like a base
Salt derived from a strong base and a strong acid • will have a pH of 7 • Salt derived from a strong base and a weak acid • will have a pH above 7 • Salt derived from a weak acid and a weak base • depends upon whether the dissolved ion acts as • an acid or a base as determined by the size of • the Ka or Kb
Acid-Base Character and Chemical Structure two things to consider polarity difference and strength of the bond HF > HCl > HBr > HI (most polar least) Based on electronegativity difference HF is the most polar but a weak acid because the bond is so strong