1 / 10

ACT Problem

ACT Problem. (6a – 12) – (4a + 4) = ? 2(a+2) 2(a+4) 2(a-2) 2(a-4) 2(a-8). ACT Problem. (6a – 12) – (4a + 4) = ? Suppose a = 1. (6(1)-12) – (4(1) + 4) (6-12) – (4+4) -6 – 8 -14. ACT Problem. (6a – 12) – (4a + 4) = ? Our answer was a -14 If a = 1, then 2(a+2) = 2(3) = 6

ashley
Download Presentation

ACT Problem

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. ACT Problem (6a – 12) – (4a + 4) = ? • 2(a+2) • 2(a+4) • 2(a-2) • 2(a-4) • 2(a-8)

  2. ACT Problem (6a – 12) – (4a + 4) = ? Suppose a = 1. (6(1)-12) – (4(1) + 4) (6-12) – (4+4) -6 – 8 -14

  3. ACT Problem (6a – 12) – (4a + 4) = ? Our answer was a -14 If a = 1, then • 2(a+2) = 2(3) = 6 • 2(a+4) = 2(5) = 10 • 2(a-2) = 2(-1) = -2 • 2(a-4) = 2(-3) = -6 • 2(a-8) = 2(-7) = -14

  4. Vertical Angles and Transversals

  5. Naming an Angle 4 Ways By the points that Compose it: <NMO or <OMN By the vertex (or pivot point of the angle): <M Or the number associated with it: <1

  6. Vertical Lines Vertical lines are opposite each other. They are always equal.

  7. Transversal of Parallel Lines Angles 1=3=5=7 Angles 2=4=6=8

  8. Angles Formed by a Transversal Alternate exterior Alternate interior

  9. Angles Formed by a Transversal Corresponding Consecutive Interior

  10. Solving for x Set up the information you know and solve for x as you would in algebra: 2x + 4 + 38 = 90 2x + 42 = 90 -42 -42 2x = 48 2 2 x = 24 2x + 4

More Related