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CPCTC

CPCTC. HOMEWORK: Lesson 4.6/1-9 , 18 Chapter 4 Test - FRIDAY. Prove it!. CPCTC C orresponding P arts of C ongruent T riangles are C ongruent. We say: Corresponding Parts of Congruent Triangles are Congruent or CPCTC for short

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CPCTC

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  1. CPCTC HOMEWORK: Lesson 4.6/1-9, 18 Chapter 4 Test - FRIDAY

  2. Prove it! CPCTC Corresponding Parts of Congruent Triangles are Congruent

  3. We say: Corresponding Parts of Congruent Triangles are Congruent or CPCTC for short • Once you have proven two triangles congruent using one of the short cuts, the rest of the parts of the triangle you haven’t proved directly are also congruent! CPCTC

  4. Take the 1st Given and MARK it on the picture • Write this Given in the PROOF & its reason (given) • If the Given is NOT a  stmt, write the  stmt to match Continue until there are no more Given • Do you have 3 stmts? • If not, look for built-in parts • Do you have triangles? • If not, write CNBD • Write the triangle congruence and reason. • If the PROVE is a pair of corresponding parts Write the congruency & CPCTC as the reason Steps To Write a Proof

  5. CPCTC example Given: TV  WV, TW bisects UX Prove: TU  WX PROOF: TV  WV Given TW bisects UX Given UV  VX Definition of segment bisector TVU  WVX VA ΔTUV  ΔWXV SAS TU  WX CPCTC MUST Prove Triangles  1st, before showing corresponding parts are 

  6. Corresponding Parts of Congruent Triangles are Congruent. CPCTC You can only use CPCTCin a proof AFTERyou have proven a TRIANGLE congruence.

  7. Corresponding parts of congruent triangles are congruent. Corresponding parts of congruent triangles are congruent. Corresponding parts of congruent triangles are congruent. Corresponding parts of congruent triangles are congruent.

  8. A PROOF: Prove: AB  DE Given: , <C <F, given <C <F given given B C D SAS F E CPCTC

  9. Given: JO  SH; O is the midpoint of SH Prove: <S <H PROOF: JO  SH given < JOS < JOH prop of  lines SAS O is the midpoint of SH given def of midpt <S <H CPCTC reflexive prop

  10. A C 2 1 E Given: BC bisects AD A  D Prove: AB DC B D PROOF: BC bisects AD given AE  ED def segment bisector ASA A   D given AB  DC 1  2 VA CPCTC

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