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EXAMPLE 1

Write a two-column proof for the situation in Example 4 from Lesson 2.5. 4. m ∠ 1 + m ∠ 2 = m ∠ DBC. m ∠ 1 = m ∠ 3. GIVEN:. m ∠ EBA = m ∠ DBC. PROVE:. 4. Angle Addition Postulate. REASONS. m ∠ EBA = m ∠ DBC. STATEMENT. 5. 5.

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EXAMPLE 1

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  1. Write a two-column proof for the situation in Example 4 from Lesson 2.5. 4. m∠ 1+m∠ 2=m∠ DBC m∠ 1=m∠ 3 GIVEN: m∠ EBA=m∠ DBC PROVE: 4. Angle Addition Postulate REASONS m∠ EBA= m∠ DBC STATEMENT 5. 5. Transitive Property of Equality 1. 1. m∠ 1=m∠ 3 Given 2. Angle Addition Postulate 2. m∠ EBA=m∠ 3+m∠ 2 3. Substitution Property of Equality 3. m∠ EBA=m∠ 1+m∠ 2 EXAMPLE 1 Write a two-column proof

  2. 1. Four steps of a proof are shown. Give the reasons for the last two steps. for Example 1 GUIDED PRACTICE GIVEN :AC = AB + AB PROVE :AB = BC

  3. ANSWER GIVEN :AC = AB + AB PROVE :AB = BC REASONS STATEMENT 1. 1. AC = AB + AB Given 2. 2. AB + BC = AC Segment Addition Postulate 3. 3. AB + AB = AB + BC Transitive Property of Equality 4. 4. AB = BC Subtraction Property of Equality for Example 1 GUIDED PRACTICE

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