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MGMT 276: Statistical Inference in Management Spring, 2014. Guidelines for ANOVA homework. Homework Assignment #17 Due April 17 th. Homework Guidelines. Homework. Homework. Type of major in school. 4 (accounting, finance, hr, marketing). Grade Point Average. Homework. 0.05. 2.83.
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MGMT 276: Statistical Inference in ManagementSpring, 2014 Guidelines for ANOVA homework Homework Assignment #17 Due April 17th
Homework Guidelines
Type of major in school 4 (accounting, finance, hr, marketing) Grade Point Average Homework 0.05 2.83 3.02 3.24 3.37
0.3937 0.1119 If observed F is bigger than critical F:Reject null & Significant! If observed F is bigger than critical F:Reject null & Significant! 0.3937 / 0.1119 = 3.517 Homework 3.517 3.009 If p value is less than 0.05:Reject null & Significant! 3 24 0.03 4-1=3 # groups - 1 # scores - number of groups 28 - 4=24 # scores - 1 28 - 1=27
Yes Homework = 3.517; p < 0.05 F (3, 24) The GPA for four majors was compared. The average GPA was 2.83 for accounting, 3.02 for finance, 3.24 for HR, and 3.37 for marketing. An ANOVA was conducted and there is a significant difference in GPA for these four groups (F(3,24) = 3.52; p < 0.05).
Average for each group(We REALLY care about this one) Number of observations in each group Just add up all scores (we don’t really care about this one)
Number of groups minus one(k – 1) 4-1=3 “SS” = “Sum of Squares”- will be given for exams Number of people minus number of groups (n – k) 28-4=24
SS between df between SS within df within MS between MS within
Type of executive 3 (banking, retail, insurance) Hours spent at computer 0.05 10.8 8 8.4
11.46 2 If observed F is bigger than critical F:Reject null & Significant! If observed F is bigger than critical F:Reject null & Significant! 11.46 / 2 = 5.733 5.733 3.88 If p value is less than 0.05:Reject null & Significant! 2 12 0.0179
Yes p < 0.05 F (2, 12) = 5.73; The number of hours spent at the computer was compared for three types of executives. The average hours spent was 10.8 for banking executives, 8 for retail executives, and 8.4 for insurance executives. An ANOVA was conducted and we found a significant difference in the average number of hours spent at the computer for these three groups , (F(2,12) = 5.73; p < 0.05).
Average for each group(We REALLY care about this one) Number of observations in each group Just add up all scores (we don’t really care about this one)
Number of groups minus one(k – 1) 3-1=2 “SS” = “Sum of Squares”- will be given for exams Number of people minus number of groups (n – k) 15-3=12
SS between df between SS within df within MS between MS within