1 / 5

Unit 12: Acids and Bases

Unit 12: Acids and Bases. Section 3: Calculating [H 3 O + ] and [OH - ] from pH. Formula Manipulation. pH = -log [H 3 O + ] log [H 3 O + ] = -pH [H 3 O + ] = antilog (-pH) [H 3 O + ] = 10 -pH  formula to find [H 3 O + ] concentration. Sample Problems.

ataret
Download Presentation

Unit 12: Acids and Bases

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Unit 12: Acids and Bases Section 3: Calculating [H3O+] and [OH-] from pH

  2. Formula Manipulation • pH = -log [H3O+] • log [H3O+] = -pH • [H3O+] = antilog (-pH) • [H3O+] = 10-pH formula to find [H3O+] concentration

  3. Sample Problems • Determine the [H3O+] concentration of an aqueous solution that has a pH of 4.0. Is the solution acidic, basic, or neutral? • Since the pH is less than 7.0, the solution is acidic • [H3O+] = 10-pH [H3O+] = 10-4 1.0 x 10-4 M

  4. Sample Problems • Determine the [H3O+] and [OH-] concentration for a solution that has a pH of 7.52. Is the solution acidic, basic, or neutral? • Since pH is greater than 7.0, the solution is slightly basic • [H3O+] = 10-pH [H3O+] = 10-7.52 3.0 x 10-8M • pOH = 14 – 7.52  6.48 • [OH-] = 10-pOH  [OH-] = 10-6.48 3.3 x 10-7 M

  5. Sample Problems • Determine the [H3O+] and [OH-] concentration for a solution that has a pOH of 2.35. Is the solution acidic, basic, or neutral? • Since the pOH is less than 7.0, the solution is basic • [OH-] = 10-pOH  [OH-] = 10-2.35 4.5 x 10-3 M • pH = 14 – 2.35  11.65 • [H3O+] = 10-pH [H3O+] = 10-11.65 2.2 x 10-12 M

More Related