1 / 13

Quadratic Word Problems WS 2 Solutions

Quadratic Word Problems WS 2 Solutions. #1. 10 inches. 15 cm by 7 cm. #2. a. 156.25 ft b. 6.25 sec c. 0.55 & 5.70 sec. #3. #4. 72 units. #5. 96 cm. #6. Height is 5.25 m or 5 m and 25 cm Distance is 3.79 meters or 3 m and 79 cm. #1. 2x + 15. 2x + 20. 0.8188 ft x 12 in/ft.

austin-cooper
Download Presentation

Quadratic Word Problems WS 2 Solutions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Quadratic Word Problems WS 2 Solutions #1 10 inches 15 cm by 7 cm #2 a. 156.25 ft b. 6.25 sec c. 0.55 & 5.70 sec #3 #4 72 units #5 96 cm #6 Height is 5.25 m or 5 m and 25 cm Distance is 3.79 meters or 3 m and 79 cm

  2. #1 2x + 15 2x + 20 0.8188 ft x 12 in/ft About 10 inches

  3. #2 Perimeter = 44 cm Area = 105 sq. cm Width = W 2L + 2W = 44 L + W = 22 Length = L L = 22 - W The dimensions of the rectangle are 15 cm by 7 cm (L)(W) = 105 (22 - W)(W) = 105 22W – W2 = 105 W2 – 22W + 105 = 0 (W - 15)(W - 7) = 105

  4. #3a h = -16t2 + 100t First find Axis of Symmetry Plug it in to get the vertex Solving for h will give the maximum point (or highest point)

  5. Two ways to solve … #3b h = -16t2 + 100t Why does this work? Alternate solution 0 = -16t2 + 100t 0 = -4t(4t – 25) t = 0 or 6.25

  6. #3c h = -16t2 + 100t 50 = -16t2 + 100t 16t2 - 100t + 50 = 0 8t2 - 50t + 25 = 0

  7. #4 x x x + 6 x + 9

  8. Width = w w - 4 3w - 4 Length = 3w Volume = L x W x H 512 = (3w - 4)(w - 4)(2) 256 = (3w - 4)(w – 4) Perimeter = 96 cm 256 = 3w2 – 16w + 16 0 = 3w2 – 16w - 240 0 = (w – 12)(3w + 20) Width = 12 cm

  9. #6 Mr. Lomas (at least the way I remember me) …. Maximum height (at vertex) height when I hit the water? 3 meters Distance from board when entering water?

  10. Maximum height of 525 cm

  11. #7 Equation: y = x2 - 10x + 15 Direct: Up Width: Standard L of S: x = 5 Vertex: (5, -10) y-int: (0, 15) Roots:

  12. #8 Equation: y = -2x2 + 8 Direct: Down Width: Narrow L of S: x = 0 Vertex: (0, 8) y-int: (0, 8) Roots: 2 or -2

  13. #9 Equation: y = (1/4)x2 - 2x - 5 Direct: Up Width: Wide L of S: x = 4 Vertex: (4, -9) y-int: (0, -5) Roots: 10 or -2

More Related