1 / 8

Factoring a Polynomial

Factoring a Polynomial. Example 1: Factoring a Polynomial. Completely factor x 3 + 2 x 2 – 11 x – 12. Use the graph or table to find at least one real root. . x = -4 is a real root because it is an x-intercept. Since x = -4 is a root, (x + 4) is a factor of the original cubic equation.

avital
Download Presentation

Factoring a Polynomial

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Factoring a Polynomial

  2. Example 1: Factoring a Polynomial Completely factor x3+ 2x2– 11x – 12 Use the graph or table to find at least one real root. x = -4 is a real root because it is an x-intercept. Since x = -4 is a root, (x + 4) is a factor of the original cubic equation. Now use polynomial division to “factor out” the (x + 4).

  3. Example 1: Factoring a Polynomial Completely factor x3+ 2x2– 11x – 12 Now we can rewrite the cubic: x2 -2x -3 x x3 -2x2 -3x This quadratic can be factored using old techniques: (x + 1)(x – 3) + 4 4x2 -8x -12 Since the graph of the cubic had more than one real root, this may be able to be factored more. x3 + 2x2– 11x – 12 Thus, the completely factored form is:

  4. Let’s try another example.

  5. Example 2: Factoring a Polynomial Completely factor x4 – x3 + 4x – 16 Use the graph or table to find at least one real root. x = -2 is a real root because it is an x-intercept. Since x = -2 is a root, (x + 2) is a factor of the original degree 4 equation. Now use polynomial division to “factor out” the (x + 2).

  6. Example 2: Factoring a Polynomial Completely factor x4 – x3 + 4x – 16 Now we can rewrite the degree 4 equation: x3 -3x2 6x -8 x x4 -3x3 6x2 -8x Let’s check the graph of this cubic to see if it has a real root. + 2 2x3 -6x2 12x -16 Since the graph of the degree 4 equation had more than one real root, this may be able to be factored more. x4 – x3 + 0x2 + 4x – 16 Make sure to include all powers of x

  7. Example 2: Factoring a Polynomial Completely factor x4 – x3 + 4x – 16 Current Factored form: Use the graph or table of the cubic in the factored form to find at least one real root. x = 2 is a real root because it is an x-intercept. Since x = 2 is a root, (x – 2) is a factor of the cubic in the factored form. Now use polynomial division to “factor out” the (x – 2) of the cubic in the factored form.

  8. Example 2: Factoring a Polynomial Completely factor x4 – x3 + 4x – 16 Current Factored form: Now we can rewrite the current factored form as: x2 -x 4 x x3 -x2 4x This quadratic can NOT be factored using old techniques (No x-intercepts). – 2 -2x2 2x -8 Since the graph of the cubic had only one real root, this may NOT be able to be factored more. x3 – 3x2 + 6x – 8 Thus, the completely factored form is:

More Related