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Chapter 25 Capacitance-II In the last lecture: we calculated the capacitance C of a system of two isolated conducto

Chapter 25 Capacitance-II In the last lecture: we calculated the capacitance C of a system of two isolated conductors. We also calculated the capacitance for some simple geometries. In this chapter we will cover the following topics:

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Chapter 25 Capacitance-II In the last lecture: we calculated the capacitance C of a system of two isolated conducto

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  1. Chapter 25 Capacitance-II In the last lecture: we calculated the capacitance C of a system of two isolated conductors. We also calculated the capacitance for some simple geometries. In this chapter we will cover the following topics: -Methods of connecting capacitors (in series , in parallel). -Equivalent capacitance. -Energy stored in a capacitor. -Behavior of an insulator (a.k.a. dielectric) when placed in the electric field created in the space between the plates of a capacitor. -Gauss’ law in the presence of dielectrics. (25 - 1)

  2. HITT An electron moves from point i to point f, in the direction of a uniform electric field. During this displacement: A. the work done by the field is positive and the potential energy of the electron-field system increases B. the work done by the field is negative and the potential energy of the electron-field system increases C. the work done by the field is positive and the potential energy of the electron-field system decreases D. the work done by the field is negative and the potential energy of the electron-field system decreases E. the work done by the field is positive and the potential energy of the electron-field system does not change j i

  3. (25 - 9)

  4. (25 - 10)

  5. (25 - 11)

  6. (25 - 12)

  7. A question • What is the equivalent capacitance between the points A and B? • 1 μF • B. 2 μF • 4 μF • 10μF • None of these A B What would a 10V battery do, i.e. how much charge will it provide, when it is connected across A and B? 40 μC

  8. -q' q' - + dq' - + - + - + - + V' Charge A q q' Voltage B O V V' (25 - 13)

  9. -q q - + - + - + A A - + - + d (25 - 14)

  10. q V -q q' V -q' V q -q V' q -q (25 - 15)

  11. q V -q q' V -q' V q -q V' q -q (25 - 16)

  12. conductor dielectric q (25 - 17)

  13. (25 - 18)

  14. (25 - 19)

  15. S S (25 - 20)

  16. (25 - 21)

  17. HITT A parallel-plate capacitor has a plate area of 0.2m2 and a plate separation of 0.1 mm. To obtain an electric field of 2.0 x 106 V/m between the plates, the magnitude of the charge on each plate should be: A. 8.9 x 10-7 C B. 1.8 x 10-6 C C. 3.5 x 10-6 C D. 7.1 x 10-6 C E. 1.4 x 10-5 C

  18. A question • Each of the four capacitors shown is 500 μF. The voltmeter reads 1000V. The magnitude of the charge, in coulombs, on each capacitor plate is: A. 0.2 B. 0.5 C. 20 D. 50 E. none of these

  19. Question • A parallel-plate capacitor has a plate area of 0.3m2 and a plate separation of 0.1mm. If the charge on each plate has a magnitude of 5x10-6 C then the force exerted by one plate on the other has a magnitude of about: • A. 0 B. 5N C. 9N D. 1 x104 N E. 9 x 105 N

  20. Question • A parallel-plate capacitor has a plate area of 0.3m2 and a plate separation of 0.1mm. If the charge on each plate has a magnitude of 5x10-6 C then the force exerted by one plate on the other has a magnitude of about: • 0 • 5N • 0. 9N • 1 x104 N • 9 x 105 N The electric field = σ/2εo why?

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