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Solving Quadratics Equations

Solving Quadratics Equations. With Professor Owl Created by Robbie Smith. Solve by Graphing. Quadratic Term: ax² Linear Term: bx Constant Term: c. In order to have a solution, the line or parabola must touch the x-axis once or twice. If it doesn’t touch at all, there is no solution.

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Solving Quadratics Equations

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  1. Solving Quadratics Equations With Professor Owl Created by Robbie Smith

  2. Solve by Graphing Quadratic Term: ax² Linear Term: bx Constant Term: c In order to have a solution, the line or parabola must touch the x-axis once or twice. If it doesn’t touch at all, there is no solution. You must also find the vertex and axis of symmetry

  3. Solve by Graphing • To find the points, you can make a table! Then graph the results. Ex. x²+6x+14=y Vertex: (-3,5) Axis or Sym: -3 Solution: None This graph shows that there is no solution.

  4. Solve by Factoring • Remember: Most equations can be factored, but not all equations can be factored. • Here are some examples of factoring. Unlike the last example which was already factored, you must factor this one. Ex. 16x² -9=0 (4x+3)(4x-3)=0 4x+3=0 4x-3=0 -3 -3 +3 +3 4x=-34x=3 4 4 4 X=-3 x=3 4 4 Ex. (x+5)(3x-2)=0 X+5=0 3x-2=0 -5 -5 +2 +2 X=-5 3x=2 3 3 x=2 3

  5. Solve by Factoring • More Examples Set the equation equal to zero Ex. x²+16=8x -8x -8x x²-8x+16=0 (x-4)(x-4)=0 x-4=0 +4 +4 x=4 Write in Proper Form Ex. 8x² -2=-2x +2x +2x 8x² -2=0 x²-16=0 (8x+4)(8x-4) 8 (x+4)(8x-4) x=-4 x=1 2 Ex. 3x²+6x=0 3x(x+2)=0 x= 0 x= -2

  6. Completing the Square • Examples of Perfect Squares x²+4x+4 (x+2)(x+2)=(x+2)² x²-8+16 (x-4)(x-4)=(x-4)² x²+14x+49 (x+7)(x+7)=(x+7)² To find the constant, do the following: Divide Linear by 2 Then square it. x²+4x+? 4/2=2 2²=4 x²+4x+4

  7. Completing the Square • Examples x²+4-10=0 +10 +10 x²+4x=10 4/2=2 2²=4 x²+4x+4=10+4 (x+2)²=14 √(x+2)²=√14 x+2=√14 x=-2+√14 x=-2-√14 3x²+6x-9=0 3 3 3 x²+2x-3=0 x²+2x+1=3+1 √(x+1)=√4 x+1=2 x+1=-2 x=1 x=-3

  8. Solve by the Quadratic Formula • When you get an equation, it looks like this: ax²+bx+c When using the quadratic formula, use this formula: x=-b±√b²-4ac 2a The Discriminant: b²-4ac (Very Important) It tells you the numbers, root, and solutions. Sweet! Let’s see an example!

  9. Solve by the Quadratic Formula x=-6±12 2(3) x=-6+12 6 x=-6-12 6 3x²+6x-9=0 6²-4(3)(-9) 36+108=144 144: Two Reals Rational x=1 x=-3 You must find the discriminant! Discriminant: Negative-2 Imaginary Solutions Zero- 1 Real Solution Positive-perfect Square- 2 Reals Rational Positive-Non-perfect square- 2 Reals Irrational

  10. And That’s It!

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