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Step 1:Think of 3 different 1-digit numbers.

Trick 1:. Step 1:Think of 3 different 1-digit numbers. Step 2: Form them into 2-digit numbers such that there are 6 combinations. Step 3: Add them up. Step 4: Divide the sum in step 2 by the sum of your 3 different numbers. Don’t tell your answer to anyone yet!.........

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Step 1:Think of 3 different 1-digit numbers.

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  1. Trick 1: Step 1:Think of 3 different 1-digit numbers. Step 2: Form them into 2-digit numbers such that there are 6 combinations. Step 3: Add them up. Step 4: Divide the sum in step 2 by the sum of your 3 different numbers. Don’t tell your answer to anyone yet!......... Step 5: Wait for further instructions.

  2. Hmm……Why? Let the 3 numbers be T, D & N. The 6 combinations – TD, TN, DT, DN, NT, ND When you add them up: TD TN + DT DN NT ND 20(T+D+N)+2(T+D+N)=22(T+D+N) So…, Sum of the 6 combinations 22(T+D+N) Sum of 3 numbers = T+D+N = 22

  3. Trick 2: Step 1: Think of a number. Step 2: Add 2 Step 3: Multiply by 5 Step 4: Add 15 Step 5: Multiply by 2 Step 6: Say out your answer! (Your answer must have a 0 behind, or else you have to repeat the steps all over again!) Aha! I can read your mind. Your number is ……!

  4. How did I derive at the answer? -Simply remove the 0 from the product and minus 5. What’s behind all this: Let x be the number. So, the steps would be… • x • x+2 • 5(x+2)= 5x+10 • 5x+10+15= 5x+25 • 2(5x+25)= 10x+50 = 10(x+5) So, when the 0 is removed, 10(x+5) is divided by 10 and the number becomes x+5. When we minus 5, x, which is the number, is obtained as x+5-5= x.

  5. Thank You!

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