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Factorising. Method 1 : Common Factors. e.g. means. so, x is a factor of both terms. It is a common factor. Common factor. So,. Exercises. Factorise the following by taking out the common factors. 1. 2. 3. 4. 5. 6. 7. 8. Factorising. Method 3 : Trinomials x 2 +bx+c.
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Factorising Method 1: Common Factors e.g. means so, xis a factor of both terms. It is a common factor Common factor So,
Exercises Factorise the following by taking out the common factors 1. 2. 3.
4. 5. 6. 7. 8.
Factorising Method 3: Trinomials x2+bx+c e.g. 1 or We need the factors of 4 which add up to –3 We need–3xso we want – 4xand +1x. –3x is called the linear term
Method 3: Trinomials e.g. 2 or We need the factors of 6 which add up to 7 Constant positive Signs of factors are the same
Exercises Constant positive Signs of factors are the same 1. 2 3 2. 2 3 3 4 3.
Exercises Constant negative Signs of factors are different 6 1 4. 6 1 5. 1 3 6.
Exercises 7. 8. 9. 10.
1. 6. 2. 7. 8. 3. 9. 4. 10. 5.
Method 3: Trinomials ax2+bx+c or This time we need the factors of 3 and the factors of 15
Method 3: Trinomials ax2+bx+c x`s no.s 1 5 + 3 3 will give –14 1 1 + 3 15 will not give –14 1 3 + 3 5 will not give –14 We need to find the pair which will add up to –14
Method 3: Trinomials ax2+bx+c x`s no.s We need to find the pair which will add up to –14 1 –5 + 3 –3 will give –14 (1x – 3)(3x –5) (1x )( –5)
Method 3: Trinomials ax2+bx+c This time we need the factors of 10 and the factors of –6
Method 3: Trinomials ax2+bx+c x`s no.s We need to find the pair which will add up to –11 2 2 + 5 3 will give 14
Method 3: Trinomials ax2+bx+c x`s no.s We need to find the pair which will add up to –11 2 2 + 5 –3 will give –11 (2x )( +2) (2x –3)(5x +2)
Method 3: Trinomials ax2+bx+c (2x + 1)(x – 4) (5x – 3)(x + 2) (3x – 2)(x + 7) (2x – 1)(x – 5) (3x – 5)(x + 3)
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