1 / 26

Outline

Outline. terminating and non-terminating systems analysis of terminating systems generation of random numbers simulation by Excel a terminating system a non-terminating system basic operations in Arena. Two Types of Systems  Terminating and Non-Terminating. chess piece

berget
Download Presentation

Outline

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Outline • terminating and non-terminating systems • analysis of terminating systems • generation of random numbers • simulation by Excel • a terminating system • a non-terminating system • basic operations in Arena

  2. Two Types of Systems  Terminating and Non-Terminating

  3. chess piece starts at vertex F moves equally likely to adjacent vertices to estimate E(# of moves) to reach the upper boundary GI/G/ 1 queue infinite buffer service times ~ unif[6, 10] interarrival times ~ unif[8, 12] to estimate the E[# of customers in system] N(t) … t, time B A C D E F Two Types of Systems

  4. chess piece initial condition defined by problem termination of a simulation run defined by the system estimation of the mean or probability of a random variable run length defined by number of replications GI/G/ 1 queue initial condition unclear termination of a simulation run defined by ourselves estimation of the mean or probability of the limit of a sequence of random variables run length defined by run time Two Types of Systems

  5. chess piece: a terminating systems analysis: Strong Law of Large Numbers (SLLN) and Central Limit Theorem (CLT) GI/G/ 1 queue: a non-terminating system analysis: probability theory and statistics related to but not exactly SLLN, nor CLT Two Types of Systems Terminating and Non-Terminating

  6. Analysis of Terminating Systems

  7. define Strong Law of Large Numbers - Basis to Analyze Terminating Systems • i.i.d. random variables X1, X2, … • finite mean  and variance 2

  8. What be? Strong Law of Large Numbers - Basis to Analyze Terminating Systems • a fair die thrown continuously • Xi = the number shown on the ith throw

  9. Strong Law of Large Numbers - Basis to Analyze Terminating Systems • in terminating systems, each replication is an independent draw of X • Xiare i.i.d. • E(X)  (X1 + … + Xn)/n

  10. Central Limit Theorem - Basis to Analyze Terminating Systems • interval estimate & hypothesis testing of normal random variables • t, 2, and F • i.i.d. random variables X1, X2, … of finite mean  and variance 2 • CLT: approximately normal for “large enough”n • can use t, 2, and Ffor

  11. Generation of Random Numbers & Random Variates

  12. To Generate Random Variates in Excel • for uniform [0, 1]:rand() function • for other distributions: use Random Number Generator in Data Analysis Tools • uniform, discrete, Poisson, Bernoulli, Binomial, Normal • tricks to transform • uniform [-3.5, 7.6]? • normal (4, 9)(where 4 is the mean and 9 is the variance)?

  13. To Generate the Random Mechanism • general overview, with details discussed later this semester • everything based on random variates from uniform (0, 1) • each stream of uniform (0, 1) random variates being a deterministicsequence of numbers on a round robin • “first” number in the robin to use: SEED • many simple, handy generators

  14. Simulation by Excel for Terminating Systems

  15. Examples • Example 1: Generate 1000 samples of X~ uniform(0,1) • Example 2: Generate 1000 samples of Y ~ normal(5,1) • Example 3: Generate 1000 samples of Z ~ z: 5 10 15 20 25 30 p: 0.1 0.15 0.3 0.2 0.14 0.11 • Example 4. Use simulation to estimate (a) P(X > 0.5) (b) P(2 < Y < 8) (c) E(Z) Using 10 replications, 50 replications, 500 replications, 5000 replications. Which is more accurate?

  16. Y = Examples: Probability and Expectation of Functions of Random Variables • X ~ x: 100 150 200 250 300 p(x): 0.1 0.3 0.3 0.2 0.1 • Find E(Y) and P(Y 30)

  17. Examples: Probability and Expectation of Functions of Random Variables • X ~ N(10, 4),Y ~ N(9,1), independent • estimate • P(X < Y) • Cov(X, Y) = E(XY) - E(X)E(Y)

  18. Example: Newsboy Problem  Pieces of “Newspapers” to Order • order 2012 calendars in Sept 2011 • cost: $2 each; selling price: $4.50 each • salvage value of unsold items at Jan 1 2012: $0.75 each • from historical data: demand for new calendars Demand: 100 150 200 250 300 Prob. : 0.3 0.2 0.3 0.15 0.05 • objective: profit maximization • questions • how many calendars to order • with the optimal order quantity, P(profit  400)

  19. Example: Newsboy Problem  Pieces of “Newspapers” to Order • D = the demand of the 2012 calendar • D follows the given distribution • Q = the order quantity {100, 150, 200, 250, 300} • V = the profit in ordering Q pieces • = 4.5 min (Q, D) + 0.75 max (0, Q - D) - 2Q • objective: find Q* to maximize E(V)

  20. Example: Newsboy Problem Pieces of “Newspapers” to Order • two-step solution procedure • 1 estimate E(profit) for a given Q • generate demands • find the profit for each demand sample • find the (sample) mean profit of all demand samples • 2 look for Q*, which gives the largest mean profit

  21. Example: Newsboy Problem  Pieces of “Newspapers” to Order • our simulation of 1000 samples, • Q = 100: E(V) = 250 • Q = 150: E(V) = 316.31 • Q = 200: E(V) = 348.31 • Q = 250: E(V) = 328.75 • Q = 300: E(V) = 277.17 • Q* = 200 is optimal • remarks: many papers on this issue

  22. Simulation by Excel for a Non-Terminating System

  23. Simulation a GI/G/1 Queue by its Special Properties • Dn = delay time of the nth customer; D1 = 0 • Sn = service time of the nth customer • Tn = inter-arrival time between the nst and the (n+1)st customer • Dn+1 = [Dn + Sn - Tn]+, where []+ = max(, 0) • average delay =

  24. Arena Model 03-1, Model 03-02, Model 03-03

  25. a drill press Model 03-01 • a drill press processing one type of product • interarrival times ~ i.i.d. exp(5) • service times ~ i.i.d. triangular (1,3,6) • all random quantities are independent one type of parts; parts come in and are processed one by one

  26. Model 03-02 and Model 03-03 • Model 03-02: sequential servers • Alfie checks credit • Betty prepares covenant • Chuck prices loan • Doris disburses funds • Model 03-03: parallel servers • Each employee can do any tasks

More Related