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Learn how to find Thévenin Equivalent with Dependent Sources. Explore methods, problems, and solutions in this in-depth module.
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Port Resistors and Independent Sources Only Module 10Thévenin Equivalent Circuitswith Dependent Sources Up until now… + _
VTh Review: Find the Thévenin Equivalent • Find Open Circuit Voltage VTh + _
+ RTh _ • Set sources to zero • Find net resistance RTh seen at the port
iB RB iB v1 + _ RE Set to zero (short ckt) Do NOT set to zero Port What happens when circuit has a Dependent Source? Example
Vtest RTh Itest = + + _ _ Vtest Test source Set to zero (short ckt) Dependent Source: Must Use“Test Source” Method to find RTh Rationale: RTh VTh
RTh Itest Vtest Itest = RTh + RTh _ Vtest Vtest = Itest RTh + Method B Itest _ In the Test Source method: = Vtest / RTh Method A
iB RB iB Itest = ? v1 Vtest + _ + _ RE Apply to Our Circuit Circuit with independent source set to zero • Solve the circuit for Itest • Compute Vtest /Itestto find RTh
Vtest RB – iB = iB _ Vtest RB iB + v1 + Vtest _ + RE _ + _ Apply KVL: Itest = ? Vtest
Apply KCL: Vtest RE Vtest RB Vtest RB Vtest RB Vtest RB Vtest RE KCL + _ + _ + + 1 RB RB 1 RE + + = Vtest RB Itest = ? Vtest RE Itest =
Vtest RB Vtest RB RB Itest Vtest RE Vtest RE + _ + 1 RB RB 1 RE _ Itest = Vtest + + Itest Vtest = 1 RB RB 1 RE + + Solve for RTh = Vtest/Itest
1 R1R2 R1||R2 = = R1 + R2 Resistors in Parallel 1 1 R2 1 R1 + 1 RB RB 1 RE = + + 1 + 1 RB 1 RE + RB + 1 RE Back to the main problem… Let’s look at the denominator…
Vtest RB Vtest RB RB Itest Vtest RE Vtest RE + _ + _ RB + 1 RB + 1 = Itest RE RE Vtest RTh = = Itest Solve for RTh = Vtest/Itest Itest Vtest = 1 RB RB 1 RE + +
Vtest RB Vtest RE + _ + _ X RB RTh = = RE But why? Wrong! Vtest Itest What happens if we erroneously set Dependent Source to zero? RB Itest Vtest RE
Vtest RB _ Vtest + Vtest RE + _ + _ iB RB Itest Vtest RE Vtest sets the voltage across RB Vtest across RBsets the value of iB iB sets the value of the dependent source
Itest Port + _ Find the Thévenin Equivalent Resistance of this circuit: Another Example • Set the independent source to zero • Apply a test current source iB RC RB iB V1 RE
iB = Itest + ItestRE – + Vtest = Itest RB + (+1)RE – Itest+ Itest (+1) Vtest RB + (+ 1)RE RTh = = Itest RC + ItestRB – iB RB Itest RE pause Done!
End of This Module Don’t forget to do the homework!