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IE1206 Embedded Electronics

Learn about embedded electronics, including pulse sensors, Kirchhoff's laws, transients, PWM, and more through practical exercises and labs. Contact William Sandqvist for more information.

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IE1206 Embedded Electronics

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  1. IE1206 Embedded Electronics Le1 Le2 PIC-block Documentation, Serial com Pulse sensors I, U, R, P, serial and parallell Le3 Ex1 KC1 LAB1 Pulse sensors, Menu program  Start of programing task Kirchhoffs laws Node analysis Two ports R2R AD Ex2 Le4 Two ports, AD, Comparator/Schmitt Ex3 Le5 KC2 LAB2 Transients PWM Le6 Ex4 Le7 KC3 LAB3 Step-up, RC-oscillator Ex5 Phasor j PWM CCP KAP/IND-sensor Le8 Le9 LC-osc, DC-motor, CCP PWM Le11 KC4 LAB4 Ex6 Le10 LP-filter Trafo Display Le12 Ex7 Display of programing task Le13 Written exam Trafo, Ethernet contact William Sandqvist william@kth.se

  2. Closed circuit?  discussion. Current can only flow through a circuit on condition there is a closed circuit. Describe in words the action of circuits a) … d) when when you operate the two switches. ( All the circuits are perhaps not as useful … ) William Sandqvist william@kth.se

  3. William Sandqvist william@kth.se

  4. Series resistors William Sandqvist william@kth.se

  5. Series resistors no current = not included in circuit! William Sandqvist william@kth.se

  6. Series resistors no current = not included in circuit! William Sandqvist william@kth.se

  7. William Sandqvist william@kth.se

  8. Two resistors in Parallell William Sandqvist william@kth.se

  9. Equivalent resistance (1.2) R1 = 1 R2 = 21 R3 = 42 R4 = 30  RERS = 30//(1+21//42) William Sandqvist william@kth.se

  10. William Sandqvist william@kth.se

  11. N samevalue in parallell William Sandqvist william@kth.se

  12. OK to move … Redrawn: William Sandqvist william@kth.se

  13. William Sandqvist william@kth.se

  14. Equivalent resistance (1.6) RTOT = 2+(12//12)//(24//24) // means parallell connection William Sandqvist william@kth.se

  15. Equivalent resistance (1.1) RTOT = 1//(0,5+0,5) +1//(0,5+0,5) =1//1+1//1= 0,5+0,5 = 1 William Sandqvist william@kth.se

  16. William Sandqvist william@kth.se

  17. Equivalent resistance (1.8) RTOT = (2+20//5)//(20//5+2) William Sandqvist william@kth.se

  18. William Sandqvist william@kth.se

  19. Potentiometer Appearance at our labs. William Sandqvist william@kth.se

  20. Equivalent resistance (1.10) William Sandqvist william@kth.se

  21. Equivalent resistance (1.10) a) RERS = 10/2 = 5 k William Sandqvist william@kth.se

  22. Equivalent resistance (1.10) a) RERS = 10/2 = 5 k b) RERS = 5/2 + 5/2 = 5 k William Sandqvist william@kth.se

  23. Equivalent resistance (1.10) a) RERS = 10/2 = 5 k b) RERS = 5/2 + 5/2 = 5 k c) RERS = 0  ! William Sandqvist william@kth.se

  24. William Sandqvist william@kth.se

  25. Voltage divider Voltagedivisionfactor DividedVoltage TotalVoltage According to the voltage divider formula tyou get a divided voltage, for example U1 across the resistor R1, by multiplying the total voltage U with a voltage division factor. This voltage division factor is the resistance R1 divided by the sum of all the resistorss that are in the series connection. William Sandqvist william@kth.se

  26. x x Resistive sensors, rotate and slide resistances RTOT RTOT R = RTOTx R R x relative movement/rotation 0 < x <1 William Sandqvist william@kth.se

  27. Potentiometer with load (1.11) Without RB William Sandqvist william@kth.se

  28. Potentiometer with load (1.11) At x = 0 and x = 1 then U = 0 and U = 5V. At x = 0,5 the load RB draws current from the voltage divider and this ” reduce” U. William Sandqvist william@kth.se

  29. Potentiometer with load ? Would you happen to wish for any of the non-linear relationship that exists in the figure, it costs apparently just an extra resistor R2! William Sandqvist william@kth.se

  30. William Sandqvist william@kth.se

  31. Seriel circuit (3.1) Determine the current I, its magnitude and direction. William Sandqvist william@kth.se

  32. William Sandqvist william@kth.se

  33. Serial – parallel circuits (3.4) Calculate the equivalent resistance: RERS = 2//(4//4) = 2//2 = 1 Calculate voltage over the equivalent resistor URERS Calculate current I = ? And voltage U = ? for the serial-parallel circuit in the figure. Current I = URERS/4 = 2/4 = 0,5 A Voltage William Sandqvist william@kth.se

  34. William Sandqvist william@kth.se

  35. Serial – parallel circuits (3.3) We start by calculating two equivalent resistances: Calculate current I = ? And voltage U = ? for the serial-parallel circuit in the figure. Voltage divider: William Sandqvist william@kth.se

  36. William Sandqvist william@kth.se

  37. Serial – parallel circuits (3.5) We calculates a equivalent resistance: Calculate current I = ? And voltage U = ? for the serial-parallel circuit in the figure. UR1 = 36 V. UR3 = UR3//4,5 can be calculated by voltage division: U can be calculated by voltage division: William Sandqvist william@kth.se

  38. William Sandqvist william@kth.se

  39. (3.2) OHM’s law are often enough! a) Calculate the resultant resistance RERS for the three parallel connected branches. b) Culculate current I and voltage U. c) Calculate the three currents I1I2 and I3 together with the voltage U1 over 3 -resistor. William Sandqvist william@kth.se

  40. OHM’s law … William Sandqvist william@kth.se

  41. OHM’s law … RERS William Sandqvist william@kth.se

  42. OHM’s law … RERS William Sandqvist william@kth.se

  43. OHM’s law … RERS William Sandqvist william@kth.se

  44. OHM’s law … William Sandqvist william@kth.se

  45. OHM’s law … William Sandqvist william@kth.se

  46. OHM’s law … William Sandqvist william@kth.se

  47. OHM’s law … William Sandqvist william@kth.se

  48. OHM’s law … OHM’s law was enough! William Sandqvist william@kth.se

  49. William Sandqvist william@kth.se

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