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CHAPTER 2 ACCELERATION. Constant Speed occurs when an object covers the same distance in equal intervals of time. Changing Speed occurs when an object covers different distance in equal intervals of time. . CONSTANT vs CHANGING SPEED.
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Constant Speed occurs when an object covers the same distance in equal intervals of time. Changing Speed occurs when an object covers different distance in equal intervals of time. CONSTANT vs CHANGING SPEED
Constant Velocity occurs when an object covers the same displacement in equal intervals of time. Changing Velocity occurs when an object covers different displacement in equal intervals of time. CONSTANT vs. CHANGING VELOCITY
CONSTANT VELOCITY constant velocity Constant Velocity Graph Position (m) Time (s)
CHANGING VELOCITY velocity Changing Velocity Graph Position (m) Time (s)
Acceleration will take place if there is a change in direction or speed of a moving object. ACCELERATION
Acceleration is the rate of change of velocity. ACCELERATION
Observe the animation of the three cars below. Which car or cars (red, green, and/or blue) are undergoing acceleration?
Velocity (m/s) Velocity (m/s) Time (s) Time (s)
PRACTICE PROBLEM 1 A car’s velocity changes from 0 m/s to 30 m/s in 10 s. Calculate the car’s acceleration.
PRACTICE PROBLEM 2 A car’s velocity changes from 10 km/h to 30 km/h, 30 min later. Calculate the car’s acceleration.
Positive or Negative acceleration Acceleration is positive Acceleration is negative Acceleration is positive Acceleration is negative
In Example A, the object is moving in the positive direction (i.e., has a positive velocity) and is speeding up. When an object is speeding up, the acceleration is in the same direction as the velocity. Thus, this object has a positive acceleration.
In Example B, the object is moving in the negative direction (i.e., has a negative velocity) and is slowing down. When an object is slowing down, the acceleration is in the opposite direction as the velocity. Thus, this object also has a positive acceleration.
1-D Constant Acceleration Equations • Vf = Vi + at • Df = Vit + ½ at2 • Vf2 = vi2 + 2a(Df-Di)
Problem #1 If a car accelerates from rest at a constant 4.2 m/s2, how long will it take for the car to reach a velocity of 37 m/s?
Problem #2 An airplane starts from rest and accelerates at a constant 2.50 m/s2 for 30.0 s before leaving the ground. How far did the airplane move before leaving the ground?
Problem #3 A parachutist descending at a speed of 10.50 m/s loses a shoe at an altitude of 38.50 m. What is the velocity of the shoe just before it hits the ground if it’s acceleration is 9.8 m/s2?
Video Clips Free Fall Displacement: http://www.smgaels.org/physics/home/videos/ForceMotion/freeFallPlot.html How does mass affect free fall?: http://www.smgaels.org/physics/home/videos/ForceMotion/massFreeFall.html Moon hammer/feather drop: http://nssdc.gsfc.nasa.gov/planetary/lunar/apollo_15_feather_drop.html