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Solve problems on Mudder's Meander, throwing darts at pi, and calculating Flesch readability score. Practice Java methods and input handling for computer evaluation of text readability.
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Homework 6 Sun., 10/12 ( MT sections ) • Due about midnight Mon., 10/13 ( WTh sections ) • Problems http://www.cs.hmc.edu/courses/2003/fall/cs5/week_06/homework.html • CS 5 website http://www.cs.hmc.edu/courses/2003/fall/cs5/ • Submission problems? Grading concerns ? let me know! email me at dodds@cs.hmc.edu
Tutors available -- lab places and times Available in the LAC Lab (Linde Activities Center) Available in Parsons PC Labs (the CIS classrooms) You may also seek out tutors away from the labs, by phone, in the dorms, etc.
HW 6 • Problem 1: The Mudder’s Meander • Problem 2: throwing darts at pi (0.5) You’ll need to write (and use) the method: 1.0 (0.5,0.5) public static boolean throwAndCheckDart() 1.0 • Problem 3: Flesch readability score You’ll need to write (and use) 2 methods: public static int numSyllables(String word) public static boolean isVowel(char c)
Computers evaluating reading? Problem: to determine the readability of text The cow is of the bovine ilk . One end is moo the other milk ! very readable • 14 words (don’t count the punctuation marks!) • 2 sentences (do count the punctuation marks!) • 16 syllables (“bovine” and “other” are the two-syllable words) 206.835 - 84.6*(syllables/word) - 1.015*(words/sentence) 206.835 - 84.6*(16/14) - 1.015*(14/2) watch out! ~ 103
Handling input code user input while (true) { String w = H.nw(); if (w.equals(“END”)) break; // do all processing here } The cow is of the bovine ilk . One end is moo the other milk ! END punctuation will ALWAYS be separated from text H.nw() handles all whitespace as word separators. Newlines are not different than spaces. the text will end with the word “END” (and it will appear nowhere else!) H.nw() will return each space-separated String as a word. counting words, sentences?
main public static void main(String[] args) { while (true) { String w = H.nw(); if (w.equals(“END”)) break; } }
// get each word in turn - using nextWord() // stop when END is seen // Stage 1: simply count up the # of Strings and print out the total @ the end
// distinguish REAL words from “.” “!” “?” // Stage 2: count up the # of words + sents. print out both totals @ the end
// count the syllables of each word // Stage 3: take in SINGLE words and print the number of syllables in each
Syllables What’s a syllable ? aeiouyAEIOUY Basically, a syllable is a cluster of 1 or more vowels in a word. vowel emerge the Put another way, a syllable is • any vowel that starts a word, plus • any vowel that follows a consonant except • a lone e at the end of the word But above all, every word must count as at least 1 syllable!
Helpful Methods public static int numSyllables(String word) simile Wrapped bungee Yes beautifully Sequoia What are some (other) English words for which this syllable algorithm is incorrect?
Checking for vowels public static boolean isVowel(char c) How would this get used to check for a vowel? How would this get used to check for a consonant?
Counting Syllables public static int numSyllables(String word)
Easy as p Visualize:
0. The user specifies how many darts to throw. // get numDarts from user // use a for loop to throw that many darts // keep track of how many hits we get // after all the darts, estimate p
1. The user specifies how accurately to estimate pi. // get tolerance from user // start throwing darts // keep track of # of hits and # of darts! // estimate p each time // continue while we are OUTSIDE the tol.
The Mudd Meander… public static void main(String[] args) { H.pl(“How many steps?”); int W = H.ni(); // get width (W) from the user int p = 0; // the student’s initial position is 0 while ( Math.abs(p) < W ) { p = p + (int)(3*Math.random())-1; // update position printPosition(p,W); // print one line } } public static void printPosition(int p, int W) { }