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Course 2: Inequalities. Solving Inequalities by Adding or Subtracting (SOL 7.15). Key Concept. Addition Property of Inequalities Words: If any number is added to each side of a true inequality, the resulting inequality is also true.
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Course 2: Inequalities Solving Inequalities by Adding or Subtracting (SOL 7.15)
Key Concept • Addition Property of Inequalities • Words: If any number is added to each side of a true inequality, the resulting inequality is also true. • Symbols: For all numbers a, b, and c, the following are true; • If a > b, then a + c > b + c • If a < b, then a + c < b + c
Key Concept • Subtraction Property of Inequalities • Words: If any number is subtracted from each side of a true inequality, the resulting inequality is also true. • Symbols: For all numbers a, b, and c, the following are true; • If a > b, then a - c > b - c • If a < b, then a - c < b - c
Addition and Subtraction Properties • Examples: • 2 < 4 6 > 3 2 + 5 < 4 + 5 6 – 2 > 3 – 2 7 < 9 4 > 1
Solve an Inequality Using Subtraction • Solve y + 5 > 11 y + 5 – 5 > 11 – 5 (Subtract 5 from both sides) y > 6 (Simplify) Check: y + 5 > 11 7 + 5 > 11 (Replace y with 7 – a number > 6) 12 > 11 (This statement is true.)
Try it! • Solve 9 + a < 3 a + 9 < 3 (You can rewrite the inequality.) a + 9 – 9 < 3 – 9 a < -6 • Check: 9 + a < 3 9 + -6 < 3 (Replace “a” with -6 or less) 3 < 3 Why can you replace a with -6?
Solve an Inequality Using Addition • Solve x – 23 < 12 x – 23 + 23 < 12 + 23 (Add 23 to both sides) x < 35 (This means all numbers less than or equal to 35) Check: x – 23 < 12 35 -23 < 12 (Replace x with 35) 12 < 12 (This statement is true.)
Solve an Inequality Using Addition • Solve -21 > d – 8 -21 + 8 > d – 8 + 8 (Add 8 to each side) -13 > d OR d < -13 • Check -21 > d – 8 -21 > -13 – 8 -21 > -21 Why can you use -13?
Try It! • Solve a – 5 > 6 a – 5 + 5 > 6 + 5 a > 11 Can you use 11 to check your solution? • Check: a – 5 > 6 12 – 5 > 6 7 > 6
Graph Solutions of Inequalities • Solve h – 1.5 < 5 h – 1.5 + 1.5 < 5 + 1.5 (Add 1.5 to each side) h < 6.5 (Simplify) • Graph the solution on a number line 5 6 7 8 • If your variable is on the left, the inequality will point in the direction you should shade
Try It! • Solve 33 < m – (-6) 33 < m + 6 (Simplify) m + 6 > 33 (You can rewrite it with the variable on the left.) m + 6 – 6 > 33 – 6 (Subtract 6 from each side) m > 27 • Graph the solution on a number line. • Place a closed circle on the number line on the number 27 • Shade to the right (positive) side
Graph Solutions of Inequalities • Solve 33 < m – (-6) 33 < m + 6 (Simplify) m + 6 > 33 (You can rewrite it with the variable on the left.) m + 6 – 6 > 33 – 6 (Subtract 6 from each side) m > 27 • Graph the solution on a number line 26 27 28 29
Use an Inequality to Solve a Problem • Katya has $12 to take to the bowling alley. If the shoe rental costs $3.75, what is the most she can spend on games and snacks? • “The most” means “no more than” or “less than or equal to” • Cost of shoe rental + games and snacks must be less than or equal to $12. • $3.75 + c < $12 $3.75 + c - $3.75 < $12 - $3.75 c < $8.25 Katya can spend no more than $8.25.
Try It! • Chris is saving money for a ski trip. He has $62.50, but his goal is to save at least $100. What is the least amount Chris needs to save to reach his goal? • Current amount + money saved must be greater than or equal to $100 • $62.50 + s > $100 $62.50 + s - $62.50 > $100 - $62.50 s > $37.50 Chris must save at least $37.50.