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Statistics for the Social Sciences

Statistics for the Social Sciences. Psychology 340 Fall 2006. Using t-tests. Outline. Review t-tests One sample, related samples, independent samples. 1 sample. Two scores per subject. The related-samples t-test can be used when:. Statistical analysis follows design. 2 samples.

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Statistics for the Social Sciences

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  1. Statistics for the Social Sciences Psychology 340 Fall 2006 Using t-tests

  2. Outline • Review t-tests • One sample, related samples, independent samples

  3. 1 sample • Two scores per subject • The related-samples t-test can be used when: Statistical analysis follows design

  4. 2 samples • Scores are related • The related-samples t-test can be used when: Statistical analysis follows design • 1 sample • Two scores per subject - OR -

  5. Performing your statistical test One sample t Related samples t One sample z Test statistic Diff. Expected by chance

  6. Effect Sizes & Power for t Test for Dependent Means Remember we don’t know these

  7. Approximate Sample Size Needed for 80% Power (.05 significance level) • Using Power and effect sizes to determine how many participants you need

  8. Compare these two means Independent samples • What are we doing when we test the hypotheses? • Consider a new variation of our memory experiment example Memory Test Memory placebo Memory patients Memory Test Memory treatment • the memory treatment sample are the same as those in the population of memory patients. • they aren’t the same as those in the population of memory patients H0: HA:

  9. 2 samples • Samples are independent • The independent samples t-test can be used when: Statistical analysis follows design

  10. Estimate of the standard error based on the variability of both samples Performing your statistical test

  11. Sample means Performing your statistical test Independent-samples t One-sample t Test statistic

  12. Population means • from the hypotheses Performing your statistical test Independent-samples t One-sample t Test statistic

  13. H0: Memory performance by the treatment group is equal to memory performance by the no treatment group. So: Performing your statistical test Independent-samples t One-sample t Test statistic • Population means • from the hypotheses

  14. We have two samples, so the estimate is based on two samples estimate is based on one sample Estimated standard error (difference expected by chance) Performing your statistical test One-sample t Test statistic

  15. “pooled variance” Number of subjects in group A Number of subjects in group B Performing your statistical test We combine the variance from the two samples

  16. “pooled variance” Variance (s2) * degrees of freedom (df) variance Performing your statistical test We combine the variance from the two samples Recall “weighted means,” need to use “weighted variances” here

  17. This is the one you use to look up your tcrit Performing your statistical test Independent-samples t • Compute your estimated standard error • Compute your t-statistic • Compute your degrees of freedom

  18. Dr. Mnemonic develops a new treatment for patients with a memory disorder. He isn’t certain what impact, if any, it will have. To test it he randomly assigns 8 patients to one of two samples. He then gives one sample the new treatment but not the other. Following the treatment period he gives both groups a memory test. The data are presented below. Use  = 0.05. Control group Exp. group 45 43 55 49 40 35 60 51 Performing your statistical test Need to compute the mean and variability for each sample

  19. Dr. Mnemonic develops a new treatment for patients with a memory disorder. He isn’t certain what impact, if any, it will have. To test it he randomly assigns 8 patients to one of two samples. He then gives one sample the new treatment but not the other. Following the treatment period he gives both groups a memory test. The data are presented below. Use  = 0.05. Control group Exp. group 45 43 55 49 SS = (45-50)2 + (55-50)2 + (40-50)2 + (60-50)2 40 35 A 60 51 = 250 Performing your statistical test Need to compute the mean and variability for each sample Control group = 50

  20. Dr. Mnemonic develops a new treatment for patients with a memory disorder. He isn’t certain what impact, if any, it will have. To test it he randomly assigns 8 patients to one of two samples. He then gives one sample the new treatment but not the other. Following the treatment period he gives both groups a memory test. The data are presented below. Use  = 0.05. Control group Exp. group 45 43 55 49 SS = (43-44.5)2 + (49- 44.5)2 + (35- 44.5)2 + (51- 44.5)2 40 35 B 60 51 = 155 Performing your statistical test Need to compute the mean and variability for each sample Exp. group = 44.5

  21. Dr. Mnemonic develops a new treatment for patients with a memory disorder. He isn’t certain what impact, if any, it will have. To test it he randomly assigns 8 patients to one of two samples. He then gives one sample the new treatment but not the other. Following the treatment period he gives both groups a memory test. The data are presented below. Use  = 0.05. Control group Exp. group 45 43 55 49 40 35 60 51 Performing your statistical test = 0.95

  22. Dr. Mnemonic develops a new treatment for patients with a memory disorder. He isn’t certain what impact, if any, it will have. To test it he randomly assigns 8 patients to one of two samples. He then gives one sample the new treatment but not the other. Following the treatment period he gives both groups a memory test. The data are presented below. Use  = 0.05. Control group Exp. group 45 43 55 49 Two-tailed • = 0.05 40 35 60 51 Performing your statistical test = 0.95 Tobs= 0.95 Tcrit=±2.447

  23. Dr. Mnemonic develops a new treatment for patients with a memory disorder. He isn’t certain what impact, if any, it will have. To test it he randomly assigns 8 patients to one of two samples. He then gives one sample the new treatment but not the other. Following the treatment period he gives both groups a memory test. The data are presented below. Use  = 0.05. Control group Exp. group 45 43 55 49 40 35 tobs=0.95 60 51 +2.45 = tcrit Performing your statistical test = 0.95 Tobs= 0.95 Tcrit=±2.447 Two-tailed • = 0.05 - Fail to Reject H0

  24. Dr. Mnemonic develops a new treatment for patients with a memory disorder. He isn’t certain what impact, if any, it will have. To test it he randomly assigns 8 patients to one of two samples. He then gives one sample the new treatment but not the other. Following the treatment period he gives both groups a memory test. The data are presented below. Use  = 0.05. Control group Exp. group 45 43 55 49 40 35 60 51 Performing your statistical test = 0.95 Tobs= 0.95 Tcrit=±2.447 Two-tailed • = 0.05 Compare Tobs < Tcrit Fail to reject the H0

  25. “pooled standard deviation” Effect Size for the t Test for Independent Means • Estimated effect size after a completed study not “pooled variance,” so take the square root of sP2

  26. Power for the t Test for Independent Means (.05 significance level)

  27. Approximate Sample Size Needed for 80% Power(.05 significance level)

  28. Statistical Tests Summary (Estimated) Standard error Design Statistical test One sample,  known One sample,  unknown Two related samples,  unknown Two independent samples,  unknown

  29. Assumptions • Each of the population distributions follows a normal curve (this is an assumption of all t-tests) • Homogeneity of variance: The two populations have the same variance • SPSS tests this using Levene’s Test • Using SPSS • Note: check out your book’s description of how to use SPSS in chapters 7 & 8 after the homework problems

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