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Jeopardy

Jeopardy. 100: Stoichiometry , Atomic/Molecular Structure. How many atoms are in 23 g of potassium? Answer. 200: Stoichiometry , Atomic/Molecular Structure.

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Jeopardy

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  1. Jeopardy

  2. 100: Stoichiometry, Atomic/Molecular Structure • How many atoms are in 23 g of potassium? • Answer

  3. 200: Stoichiometry, Atomic/Molecular Structure • A sheet of paper has a density of 0.2 g/cm3, a surface area of 93.5 in2, and a weight of 2.0 mg. What is the thickness of the sheet? • Answer

  4. 300: Stoichiometry, Atomic/Molecular Structure • Fill in the following table: • Answer

  5. 400: Stoichiometry, Atomic/Molecular Structure • Which reagent is the limiting reactant when 0.450 mol Al(OH)3 and 0.450 mol H2SO4 are allowed to react? • Answer

  6. 500: Stoichiometry, Atomic/Molecular Structure • Write the following names of the compounds: • Potassium Phosphide • Calcium Hydride • Lithium Phosphate • Answer

  7. 100 Stoich. Answer • 3.5 x 1023 atoms of potassium

  8. 200 Stoich. Answer

  9. 300 Stoich. Answer

  10. 400 Stoich. Answer

  11. 500 Stoich. Answer • Potassium Phosphide= K3P • Calcium Hydride= CaH2 • Lithium Phosphate= Li3PO4

  12. 100: Energetics • 2 O3(g)  3O2(g) ΔH= -284.6 kJ • What is the enthalpy change for this reaction per mole of O3? • Answer

  13. 200: energetics • 2 CH3OH 2 CH4 + O2 ΔH= 252.8 kJ • How much heat is transferred when 24.0 g of CH3OH is decomposed by this reaction at constant pressure? • Answer

  14. 300: energetics • The specific heat of octane is 2.22 J/g-K. How many J of heat are needed to raise the temperature of 80.0 g of octane from 13-60 °C? • Answer

  15. 400: Energetics • Using Hess’s Law: Find the ΔH for the reaction • PCl5(g) → PCl3(g) + Cl2(g), given the following reactions: • P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ • 4PCl5(g) → P4(s) + 10Cl2(g) ΔH = 3438 kJ • Answer

  16. 500: energetics • Find the ΔH for the reaction 2CO2(g) + H2O(g) → C2H2(g) + 5/2O2(g), given the following reactions: • C2H2(g) + 2H2(g) → C2H6(g) ΔH = -94.5 kJ • H2O(g) → H2(g) + 1/2O2 (g) ΔH = 71.2 kJ • C2H6(g) + 7/2O2(g) → 2CO2(g) + 3H2O(g) ΔH = -283 kJ • Answer

  17. 100 Energetics Answer • ΔH= -142.3 kJ/mol O3

  18. 200 Energetics Answer

  19. 300 Energetics Answer • q= mcΔT • q= (80.0 g)(2.22 J/g-°C)(60-13°C) • q= 8350 J

  20. 400 Energetics Answer

  21. 500 Energetics Answer

  22. 100: Acids and bases • What is the pH of a 0.04 M HCl solution? • Answer

  23. 200: Acids and bases • In the following equation, lable the acid, base, conjugate acid and conjugate base. • HC2H3O2(aq) + H2O (l) àH3O+ (aq) + C2H3O2- (aq) • Answer

  24. 300: Acids and bases • What is concentration of hydroxide ions if the pH is 8.9? • Answer

  25. 400: Acids and bases • Find the pH of a solution containing 0.33 M Acetic Acid (HC2H3O2). The Ka value for acetic acid is 1.8 x 10-5. • HC2H3O2⇔ C2H3O2- + H+ • Answer

  26. 500: Acids and bases • Caffeine is a base with a formula C8H10N4O2. If there is 0.0032 g of caffeine in a solution of 1 L, what will the pH of the solution be? Caffeine has a Kb of 4.1 x 10-4. • Answer

  27. 100 Acids/Bases answer • pH= -log (.04)= 1.40

  28. 200 Acids/Bases answer • HC2H3O2 (aq) + H2O (l) àH3O+ (aq) + C2H3O2- (aq) • HC2H3O2= acid • H2O= base • H3O+= conjugateacid • C2H3O2-= conjugate base

  29. 300 Acids/Bases answer • What is concentration of hydroxide ions if the pH is 8.9? • 14 - 8.9= 5.1= pOH • [OH-]= 10-5.1= 7.9 x 10-6 M

  30. 400 Acids/Bases answer • 1.8 x 10-5= x2/0.33 • x= 0.0024= [H+] • -log(.0024)= 2.61

  31. 500 Acids/Bases answer • 0.0032 g * (1 mol/166.18 g)= 1.92 x 10-5mol/ 1L= 1.92 x 10-5M • 4.1 x 10-4= x2/ 1.92 x 10-5 • x= 8.9 x 10-5 = [OH-] • pOH= -log (8.9 x 10-5)= 4.05 • 14 - pOH= pH= 9.95

  32. 100: Gas LAw • What are the conditions of STP? • Answer

  33. 200: Gas LAw • If 0.03 mol of gas is in a 250 mL container at 450 K, what will the pressure be? • Answer

  34. 300: Gas LAw • What volume is occupied by 2.1 g of He at a pressure of 5.6 atm at 298 K? • Answer

  35. 400: Gas LAw • If a gas has a pressure of 4.5 atm in a 1 L container and you transfer it to a 2 L container, what will the new pressure be? • Answer

  36. 500: Gas LAw • If a gas is in a 520 mL container at 298 K and you raise the temperature to 450 K, what volume will the gas occupy? • Answer

  37. 100 answer Gas LAw • Standard Temperature and Pressure: • 1 atmosphere, 273 K

  38. 200 answer Gas LAw • If 0.03 mol of gas is in a 250 mL container at 450 K, what will the pressure be? • PV=nRT • P(0.250 L)= (.03 mol)(0.0821L*atm/mol*K)(450 K) • P=4.4 atm

  39. 300 answer Gas LAw • 2.1 g He*(1 mol/4 g He)= 0.525 mol He • PV=nRT • (5.6)V= (.525)(0.0821)(298) • V= 2.3 L

  40. 400 answer: Gas LAw • P1V1= P2V2 • (4.5 atm)(1 L)= P2(2 L) • P2= 2.25 atm

  41. 500 answer Gas LAw • V1/T1=V2/T2 • (520 mL)/(298 K) = V2/ (450 K) • V2= 785 K

  42. 100: Misc. • The electron configuration [Ar]4s23d104p2 represents what element? • Answer

  43. 200: Misc. • Draw the Lewis Structure of BeF2 • Answer

  44. 300: Misc • What is the wavelength of a radiation that has a frequency of 7.9 x 10-5 seconds? • Answer

  45. 400 misc. • Write all the possible quantum (n, l, ml, ms) numbers for n=2. • Answer

  46. 500 Misc. • What is the value of the rate constant, k, for the reaction? • 2A + B2 2 AB • Answer

  47. 100 Answer misc. • Ge

  48. 200 Answer misc.

  49. 300 answer misc. • c= λν • 3 x 108 m/s= λ (7.9 x 10-5 s) • λ= 3.8 x 1012 m

  50. 400 answer misc. • n= 2 • l= 0, 1 • For l= 0 ml= 0 and ms= ±1/2 • For l= 1, ml= -1, 0, or 1 and ms= ±1/2 for each of the ml values

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