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Operational Amplifiers

Operational Amplifiers. Supplemental lecture Rick Matthews. The inverting amplifier. R2 provides negative feedback. The inverting amplifier. R2 provides negative feedback. This means V- is adjusted to V+. The inverting amplifier. R2 provides negative feedback.

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Operational Amplifiers

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  1. Operational Amplifiers Supplemental lecture Rick Matthews

  2. The inverting amplifier • R2 provides negative feedback.

  3. The inverting amplifier • R2 provides negative feedback. • This means V- is adjusted to V+.

  4. The inverting amplifier • R2 provides negative feedback. • This means V- is adjusted to V+. • V+ is zero, so V- must be zero, too.

  5. The inverting amplifier • R2 provides negative feedback. • This means V- is adjusted to V+. • V+ is zero, so V- is zero. I

  6. The inverting amplifier • R2 provides negative feedback. • This means V- is adjusted to V+. • V+ is zero, so V- is zero. I

  7. The inverting amplifier • R2 provides negative feedback. • This means V- is adjusted to V+. • V+ is zero, so V- is zero. I

  8. More generally,…

  9. More generally,… • Whatever sits in the place of R1 serves to create a current I that is a function of Vin. I=f(Vin)

  10. More generally,… • Whatever sits in the place of R1 serves to create a current I that is a function of Vin. • And whatever sits in place of R2 serves to create a voltage Vout that is a second function of I. Vout= -g(I) I=f(Vin)

  11. More generally,… • Whatever sits in the place of R1 serves to create a current I that is a function of Vin. • And whatever sits in place of R2 serves to create a voltage Vout that is a second function of I. Vout= -g(I) I=f(Vin)

  12. Example

  13. Example

  14. Example

  15. Example: Exponentiating amp

  16. Example: Exponentiating amp

  17. Example: Exponentiating amp

  18. Example: Exponentiating amp

  19. Example: Exponentiating amp

  20. Example: log amp

  21. Example: log amp

  22. Example: log amp

  23. Example: log amp

  24. Example: log amp

  25. Example: log amp

  26. Example: log amp

  27. A Multiplier log(a)+log(b) =log(ab) Vin1 Log Amp log(a) ab ExponentialAmp SummingAmp Vout Vin2 Log Amp log(b)

  28. A Divider log(a)-log(b) =log(a/b) Vin1 Log Amp log(a) a/b ExponentialAmp DifferentialAmp Vout Vin2 Log Amp log(b)

  29. Calculus Differentiator

  30. Calculus Integrator Differentiator

  31. Etc. • Can you think of a circuit to take cube roots? • We can fashion sophisticated analog computers this way.

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