250 likes | 365 Views
Reasoning with Properties of Algebra & Proving Statements About Segments. CCSS: G-CO.12. CCSS:G-CO.12.
E N D
Reasoning with Properties of Algebra &Proving Statements About Segments CCSS: G-CO.12
CCSS:G-CO.12 • Make formal geometric constructions with a variety of tools and methods (compass and straightedge, string, reflective devices, paper folding, dynamic geometric software, etc.). Copying a segment; copying an angle; bisecting a segment; bisecting an angle; constructing perpendicular lines, including the perpendicular bisector of a line segment; and constructing a line parallel to a given line through a point not on the line.
Essential Question(s) • What algebra properties apply to angles and segments? • How do we use properties of length and measure to justify segment and angle relationships? • How do we justify statements about congruent segments?
Activator: • Work with your partner. Make a list of Properties of Equality for Algebra. Give examples for each property. Solve writing down your reasoning for each step: 6x + 3 = 9(x -1).After you finish walk around to compare your results with the other groups.
Activator: • Given: AB = BC • Prove: AC = 2(BC) A B C
Objectives Review properties of equality and use them to write algebraic proofs. Identify properties of equality and congruence.
In Geometry you accept postulates & properties as true. • You use Deductive Reasoning to prove other statements. • In Algebra you accept the Properties of Equality as true also.
Algebra Properties of Equality • Addition Property: • If a = b, then a + c = b + c • Subtraction Property: • If a = b, then a – c = b – c • Multiplication Property: • If a = b, then a • c = b • c • Division Property: • If a = b, then a/c = b/c (c ≠ 0)
More Algebra Properties • Reflexive Property: • a = a (A number is equal to itself) • Symmetric Property: • If a = b, then b = a • Transitive Property: • If a = b & b = c, then a =c
2 more Algebra Properties • Substitution Properties: (Subs.) • If a = b, then “b” can replace “a” anywhere • Distributive Properties: • a(b +c) = ab + ac
A proof is an argument that uses logic, definitions, properties, and previously proven statements to show that a conclusion is true. An important part of writing a proof is giving justifications to show that every step is valid.
3x + 5 = 20 -5 -5 3x = 15 3 3 x = 5 5 = x 1. Given Statement 2. Subtr. Prop 3. Division Prop 4. Symmetric Prop Example 1: Algebra Proof
Statements 1. mAOC = 139, mAOB = x, mBOC = 2x + 10 2. mAOC = mAOB + mBOC 3. 139 = x + 2x + 10 4. 139 = 3x + 10 5. 129 = 3x 6. 43 = x 7. x = 43 Reasons 1. Given 2. Addition Prop. 3. Subs. Prop. 4. Addition Prop 5. Subtr. Prop. 6. Division Prop. 7. Symmetric Prop. Example 2 : Addition ProofGiven: mAOC = 139Prove: x = 43 A B x (2x + 10) C O
Statements AB=4+2x, BC=15 – x, AC=21 AC = AB + BC 21 = 4 + 2x + 15 – x 21 = 19 + x 2 = x x = 2 Reasons Given Segment Add. Prop. Subst. Prop. Combined Like Term. Subtr. Prop. Symmetric Prop. Example 3:Segment Addition ProofGiven: AB = 4 + 2x BC = 15 – x AC = 21Prove: x = 2 A 15 – x C 4 + 2x B
You learned in Chapter 1 that segments with equal lengths are congruent and that angles with equal measures are congruent. So the Reflexive, Symmetric, and Transitive Properties of Equality have corresponding properties of congruence.
Theorem • A true statement that follows as a result of other true statements. • All theorems MUST be proved!
2-Column Proof • Numbered statements and corresponding reasons in a logical order organized into 2 columns. statements reasons 1. 1. 2. 2. 3. 3. etc.
Geometry Properties of Congruence • Reflexive Property: AB AB A A • Symmetric Prop: If AB CD, then CD AB If A B, then B A • Transitive Prop: If AB CD and CD EF, then AB EF IF A B and B C, then A C
Theorem 2.1- Properties of Segment Congruence • Segment congruence is reflexive, symmetric, & transitive.
Statements 1. AB = BC BC = AB Reasons Given Defn. of congruent segs. Symmetric prop of = Defn. of congruent segs. Proof of symmetric part of thm. 2.1
Paragraph Proof • Same argument as a 2-column proof, but each step is written as a sentence; therefore forming a paragraph. P X Y Q • You are given that line segment PQ is congruent with line segment XY. By the definition of congruent segments, PQ=XY. By the symmetric property of equality XY = PQ. Therefore, by the definition of congruent segments, it follows that line segment XY congruent to line segment PQ.
Statements PQ=2x+5, QR=6x-15, PR=46. 2. PQ+QR=PR 3. 2x+5+6x-15=46 4. 8x-10=46 5. 8x=56 6. x=7 Reasons Given Seg + Post. Subst. prop of = Simplify + prop of = Division prop of = Ex: Given: PQ=2x+5 QR=6x-15 PR=46 Prove: x=7 P Q R
Statements Q is midpt of PR PQ=QR PQ+QR=PR QR+QR=PR 2QR=PR QR= PQ= Reasons Given Defn. of midpt Seg + post Subst. prop of = Simplify Division prop of = Subst. prop Ex: Given: Q is the midpoint of PR. Prove: PQ and QR =
What did I learn Today? • Name the property for each of the following steps. • P Q, then Q P Symmetric Prop • TU XY and XY AB, then TU AB Transitive Prop • DF DF Reflexive