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Chapter 10. Section 10.3. Exercise #1. Identify the polygon and find the sum of the measures of the angles. Octagon. (n – 2)(180°) = sum of the angles. (8 – 2)(180°) = sum of the angles. (6)(180°) = sum of the angles. 1080° = sum of the angles.
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Chapter 10 Section 10.3 Exercise #1
Identify the polygon and find the sum of the measures of the angles.
Chapter 10 Section 10.3 Exercise #11
22 yd 16 yd 16 yd 22 yd P = 16yd + 22yd + 16yd + 22yd
22 yd 16 yd 16 yd 22 yd P = 2(16yd) + 2(22yd)
22 yd 16 yd 16 yd 22 yd P = 32yd + 44yd
22 yd 16 yd 16 yd 22 yd P = 76yd
22 yd 16 yd 16 yd 22 yd The perimeter is 76 yd.
Chapter 10 Section 10.3 Exercise #17
5 ft 3 ft 4 ft 4 ft 7 ft 7 ft 2 ft 10 ft 5ft + 4ft + 2ft + 4ft + 3ft + 7ft + 10ft + 7ft P =
5 ft 3 ft 4 ft 4 ft 7 ft 7 ft 2 ft 10 ft P = 42ft
5 ft 3 ft 4 ft 4 ft 7 ft 7 ft 2 ft 10 ft The perimeter is 42 ft.
Chapter 10 Section 10.3 Exercise #23
How many feet of hedges will be needed to enclose a triangular display at an amusement park if the sides measure 62feet, 85feet, and 94feet?
94 ft 62 ft 85 ft Perimeter = 62ft + 85ft + 94ft
94 ft 62 ft 85 ft Perimeter = 241ft
94 ft 62 ft 85 ft 241 ft of hedges are needed.
Chapter 10 Section 10.3 Exercise #27
How many times must a person walk around a football field in order to walk a mile? The dimensions of a football field are 360 feet by 160 feet. One mile = 5280 feet.
360 ft 160 ft 160 ft 360 ft Perimeter = 2(160ft) + 2(360ft)
360 ft 160 ft 160 ft 360 ft Perimeter = 320ft + 720ft
360 ft 160 ft 160 ft 360 ft Perimeter = 1040 ft 1 mile = 5280 ft
360 ft 160 ft 160 ft 360 ft 5280 ft = 5.08 1040 ft
360 ft 160 ft 160 ft 360 ft A person needs to walk around a football field a little over 5 times to walk a mile.