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Fi8000 Valuation of Financial Assets

Fi8000 Valuation of Financial Assets. Spring Semester 2010 Dr. Isabel Tkatch Assistant Professor of Finance. Valuation of Options. Arbitrage Restrictions on the Values of Options Quantitative Pricing Models Binomial model A formula in the simple case An algorithm in the general case

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Fi8000 Valuation of Financial Assets

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  1. Fi8000Valuation ofFinancial Assets Spring Semester 2010 Dr. Isabel Tkatch Assistant Professor of Finance

  2. Valuation of Options • Arbitrage Restrictions on the Values of Options • Quantitative Pricing Models • Binomial model • A formula in the simple case • An algorithm in the general case • Black-Scholes model (a formula)

  3. Binomial Option Pricing Model Assumptions: • A single period • Two dates: time t=0 and time t=1 (expiration) • The future (time 1) stock price has only two possible values • The price can go up or down • The perfect market assumptions • No transactions costs, borrowing and lending at the risk free interest rate, no taxes…

  4. The stock price Assume S= $50, u= 10% and d= (-3%) Binomial Option Pricing ModelExample Su=$55 Su=S·(1+u) S=$50 S Sd=$48.5 Sd=S·(1+d)

  5. The call option price Assume X= $50, T= 1 year (expiration) Binomial Option Pricing ModelExample Cu= $5 = Max{55-50,0} Cu= Max{Su-X,0} C C Cd= $0 = Max{48.5-50,0} Cd= Max{Sd-X,0}

  6. The bond price Assume r= 6% Binomial Option Pricing ModelExample $1.06 (1+r) $1 1 $1.06 (1+r)

  7. Replicating Portfolio At time t=0, we can create a portfolio of N shares of the stock and an investment of B dollars in the risk-free bond. The payoff of the portfolio will replicate the t=1 payoffs of the call option: N·$55 + B·$1.06 = $5 N·$48.5 + B·$1.06 = $0 Obviously, this portfolio should also have the same price as the call option at t=0: N·$50 + B·$1 = C We get N=0.7692, B=(-35.1959) and the call option price is C=$3.2656.

  8. Replicating Portfolio The weights of Bonds and Stocks in the replicating portfolio are: ZB= (-$35.1959) / $3.2656 = -10.78 ZS= (0.7692 * $50) / $3.2656 = 11.78 Say you invest $100. The two equivalent investment strategies are: 1. Buy call options for $100 (i.e., buy $100 / $3.2656 = 30.62 call options) 2. Sell bonds for 10.78 * $100 = $1,078 Buy stocks for 11.78 * $100 = $1,178

  9. The put option price Assume X= $50, T= 1 year (expiration) Binomial Option Pricing ModelExample Continued Pu= $0 = Max{50-55,0} Pu= Max{X-Su,0} P P Pd= $1.5 = Max{50-48.5,0} Pd= Max{X-Sd,0}

  10. Replicating Portfoliofor the Put Option At time t=0, we can create a portfolio of N shares of the stock and an investment of B dollars in the risk-free bond. The payoff of the portfolio will replicate the t=1 payoffs of the put option: N·$55 + B·$1.06 = $0 N·$48.5 + B·$1.06 = $1.5 Obviously, this portfolio should also have the same price as the put option at t=0: N·$50 + B·$1 = P We get N=(-0.2308), B=11.9739 and the put option price is P=$0.4354.

  11. Replicating Portfolio The weights of Bonds and Stocks in the replicating portfolio are: ZB= ($11.9739) / $0.4354 = 27.5 ZS= (-0.2308 * $50) / $0.4354 = -26.5 Say you invest in one put options contract (i.e. 100 options). The two equivalent investment strategies are: 1. Buy one put options contract for $0.4354*100 = $43.54 2. Buy bonds for 27.5 * $43.54 = $1,197.35 Sell stocks for 26.5 * $43.54 = $1,153.81

  12. The price of $1 in the “up” state: The price of $1 in the “down” state: A Different Replication $0 $1 qd qu $1 $0

  13. Replicating Portfolios Using the State Prices We can replicate the t=1 payoffs of the stock and the bond using the state prices: qu·$55 + qd·$48.5 = $50 qu·$1.06 + qd·$1.06 = $1 Obviously, once we solve for the two state prices we can price any other asset in that economy. In particular we can price the call option: qu·$5 + qd·$0 = C We get qu=0.6531, qd=0.2903 and the call option price is C=$3.2656.

  14. The put option price Assume X= $50, T= 1 year (expiration) Binomial Option Pricing ModelExample Pu= $0 = Max{50-55,0} Pu= Max{X-Su,0} P P Pd= $1.5 = Max{50-48.5,0} Pd= Max{X-Sd,0}

  15. Replicating Portfolios Using the State Prices We can replicate the t=1 payoffs of the stock and the bond using the state prices: qu·$55 + qd·$48.5 = $50 qu·$1.06 + qd·$1.06 = $1 But the assets are exactly the same and so are the state prices. The put option price is: qu·$0 + qd·$1.5 = P We get qu=0.6531, qd=0.2903 and the put option price is P=$0.4354.

  16. Two Period Example • Assume that the current stock price is $50, and it can either go up 10% or down 3% in each period. • The one period risk-free interest rate is 6%. • What is the price of a European call option on that stock, with an exercise price of $50 and expiration in two periods?

  17. The Stock Price S= $50, u= 10% and d= (-3%) Suu=$60.5 Su=$55 Sud=Sdu=$53.35 S=$50 Sd=$48.5 Sdd=$47.05

  18. The Bond Price r= 6% (for each period) $1.1236 $1.06 $1.1236 $1 $1.06 $1.1236

  19. The Call Option Price X= $50 and T= 2 periods Cuu=Max{60.5-50,0}=$10.5 Cu Cud=Max{53.35-50,0}=$3.35 C Cd Cdd=Max{47.05-50,0}=$0

  20. State Prices in the Two Period Tree We can replicate the t=1 payoffs of the stock and the bond using the state prices: qu·$55 + qd·$48.5 = $50 qu·$1.06 + qd·$1.06 = $1 Note that if u, d and r are the same, our solution for the state prices will not change (regardless of the price levels of the stock and the bond): qu·S·(1+u) + qd·S·(1+d) = S qu ·(1+r)t + qd ·(1+r)t = (1+r)(t-1) Therefore, we can use the same state-prices in every part of the tree.

  21. The Call Option Price qu= 0.6531 and qd= 0.2903 Cuu=$10.5 Cu Cud=$3.35 C Cd Cdd=$0 Cu = 0.6531*$10.5 + 0.2903*$3.35 = $7.83 Cd = 0.6531*$3.35 + 0.2903*$0.00 = $2.19 C = 0.6531*$7.83 + 0.2903*$2.19 = $5.75

  22. Two Period Example • What is the price of a European put option on that stock, with an exercise price of $50 and expiration in two periods? • What is the price of an American call option on that stock, with an exercise price of $50 and expiration in two periods? • What is the price of an American put option on that stock, with an exercise price of $50 and expiration in two periods?

  23. Two Period Example • European put option - use the tree or the put-call parity • What is the price of an American call option - if there are no dividends … • American put option – use the tree

  24. The European Put Option Price qu= 0.6531 and qd= 0.2903 Puu=$0 Pu Pud=$0 P Pd Pdd=$2.955 Pu = 0.6531*$0 + 0.2903*$0 = $0 Pd = 0.6531*$0 + 0.2903*$2.955 = $0.858 PEU = 0.6531*$0 + 0.2903*$0.858 = $0.25

  25. The European Put Option Price Another way to calculate the European put option price is to use the put-call-parity restriction:

  26. The American Put Option Price qu= 0.6531 and qd= 0.2903 Puu=$0 Pu Pud=$0 PAm Pd Pdd=$2.955

  27. American Put Option Note that at time t=1 the option buyer will decide whether to exercise the option or keep it till expiration. If the payoff from immediate exercise is higher than the value of keeping the option for one more period (“European”), then the optimal strategy is to exercise: If Max{ X-Su,0 } > Pu(“European”) => Exercise

  28. The American Put Option Price qu= 0.6531 and qd= 0.2903 Puu=$0 Pu Pud=$0 P Pd Pdd=$2.955 Pu = Max{ 0.6531*0 + 0.2903*0 , 50-55 } = $0 Pd = Max{ 0.6531*0 + 0.2903*2.955 , 50-48.5 } = 50-48.5 = $1.5 PAm = Max{ 0.6531*0 + 0.2903*1.5 , 50-50 } = $0.4354 > $0.2490 = PEu

  29. Determinants of the Valuesof Call and Put Options

  30. Black-Scholes Model • Developed around 1970 • Closed form, analytical pricing model • An equation • Can be calculated easily and quickly (using a computer or even a calculator) • The limit of the binomial model if we are making the number of periods infinitely large and every period very small – continuous time • Crucial assumptions • The risk free interest rate and the stock price volatility are constant over the life of the option.

  31. C – call premium S – stock price X – exercise price T – time to expiration r – the interest rate σ – std of stock returns ln(z) – natural log of z e-rT – exp{-rT} = (2.7183)-rT N(z) – standard normal cumulative probability Black-Scholes Model

  32. The N(0,1) Distribution pdf(z) N(z) μz=0 z

  33. C – ? S – $47.50 X – $50 T – 0.25 years r – 0.05 (5% annual rate compounded continuously) σ – 0.30 (or 30%) Black-Scholes example

  34. C – ? S – $47.50 X – $50 T – 0.25 years r – 0.05 (5% annual rate compounded continuously) σ – 0.30 (or 30%) Black-Scholes Example

  35. Black-Scholes Model • Continuous time and therefore continuous compounding • N(d) – loosely speaking, N(d) is the “risk adjusted” probability that the call option will expire in the money (check the pricing for the extreme cases: 0 and 1) • ln(S/X) – approximately, a percentage measure of option “moneyness”

  36. P – Put premium S – stock price X – exercise price T – time to expiration r – the interest rate σ – std of stock returns ln(z) – natural log of z e-rT – exp{-rT} = (2.7183)-rT N(z) – standard normal cumulative probability Black-Scholes Model

  37. P – ? S – $47.50 X – $50 T – 0.25 years r – 0.05 (5% annual rate compounded continuously) σ – 0.30 (or 30%) Black-Scholes Example

  38. The Put Call Parity The continuous time version (continuous compounding):

  39. Stock Return Volatility One approach: Calculate an estimate of the volatility using the historical stock returns and plug it in the option formula to get pricing

  40. Stock Return Volatility Another approach: Calculate the stock return volatility implied by the option price observed in the market (a trial and error algorithm)

  41. Option Price and Volatility Let σ1 < σ2 be two possible, yet different return volatilities; C1, C2 be the appropriate call option prices; and P1, P2 be the appropriate put option prices. We assume that the options are European, on the same stock S that pays no dividends, with the same expiration date T. Note that our estimate of the stock return volatility changes. The two different prices are of the same option, and can not exist at the same time! Then, C1 ≤ C2 and P1 ≤ P2

  42. C – $2.5 S – $47.50 X – $50 T – 0.25 years r – 0.05 (5% annual rate compounded continuously) σ – ? Implied Volatility - example

  43. C – ? S – $47.50 X – $50 T – 0.25 years r – 0.05 (5% annual rate compounded continuously) σ – 0.30 (or 30%) Implied Volatility - example

  44. C – ? S – $47.50 X – $50 T – 0.25 years r – 0.05 (5% annual rate compounded continuously) σ – 0.40 (or 40%) Implied Volatility - example

  45. C – ? S – $47.50 X – $50 T – 0.25 years r – 0.05 (5% annual rate compounded continuously) σ – 0.35 (or 35%) Implied Volatility - example

  46. Application: Portfolio Insurance Options can be used to guarantee minimum returns from an investment in stocks. Purchasing portfolio insurance (protective put strategy): Long one stock; Buy a put option on one stock; If no put option exists, use a stock and a bond to replicate the put option payoffs.

  47. Portfolio Insurance Example You decide to invest in one share of General Pills (GP) stock, which is currently traded for $56. The stock pays no dividends. You worry that the stock’s price may decline and decide to purchase a European put option on GPs stock. The put allows you to sell the stock at the end of one year for $50. If the std of the stock price is σ=0.3 (30%) and rf=0.08 (8% compounded continuously), what is the price of the put option? What is the CF from your strategy at time t=0? What is the CF at time t=1 as a function of 0<ST<100?

  48. Portfolio Insurance Example What if there is no put option on the stock that you wish to insure? - Use the B&S formula to replicate the protective put strategy. What is your insurance strategy? What is the CF from your strategy at time t=0? Suppose that one week later, the price of the stock increased to $60, what is the value of the stocks and bonds in your portfolio? How should you rebalance the portfolio to keep the insurance?

  49. Portfolio Insurance Example The B&S formula for the put option: -P = -Xe-rT[1-N(d2)]+S[1-N(d1)] Therefore the insurance strategy (Original portfolio + synthetic put) is: Long one share of stock Long X·[1-N(d2)] bonds Short [1-N(d1)] stocks

  50. Portfolio Insurance Example The total time t=0 CF of the protective put (insured portfolio) is: CF0 = -S0-P0 = -S0-Xe-rT[1-N(d2)]+S0[1-N(d1)] = -S0[N(d1)]-Xe-rT[1-N(d2)] And the proportion invested in the stock is: wstock=-S0[N(d1)]/{-S0[N(d1)]-Xe-rT[1-N(d2)]}

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