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PHYS 3446 – Lecture #2. Wednesday, Aug. 30, 2006 Dr. Jae Yu. Introduction History on Atomic Models Rutherford Scattering Rutherford Scattering with Coulomb force Scattering Cross Section Measurement of Cross Sections. Announcements.
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PHYS 3446 – Lecture #2 Wednesday, Aug. 30, 2006 Dr. JaeYu • Introduction • History on Atomic Models • Rutherford Scattering • Rutherford Scattering with Coulomb force • Scattering Cross Section • Measurement of Cross Sections PHYS 3446, Fall 2006 Jae Yu
Announcements • Mail distribution list is ready. Go ahead and subscribe! • 5 points extra credit if done by next Wednesday, Sept. 6 • 3 points extra credit if done by next Friday, Sept. 8 • Extra credit opportunities • Obtain a particle data booklet and a pocket diary • http://pdg.lbl.gov/pdgmail/ • Subscribe to the Symmetry Magazine (free!) • http://www.symmetrymagazine.org • Request for printed copies • Subscribe to the printed copies of CERN Courier Magazine • http://www.cerncourier.com/ • Send e-mail to Janice Voss at vosses@aol.com • 3 points each if done by Wednesday, Sept. 6. PHYS 3446, Fall 2006 Jae Yu
Why do Physics? Exp.{ Theory { • To understand nature through experimental observations and measurements (Research) • Establish limited number of fundamental laws, usually with mathematical expressions • Predict nature’s courses • Theory and Experiment work hand-in-hand • Theory works generally under restricted conditions • Discrepancies between experimental measurements and theory presents opportunities to quantum leap • Improves our everyday lives, though some laws can take a while till we see amongst us PHYS 3446, Fall 2006 Jae Yu
Matter Molecule Atom Nucleus Baryon Quark (Hadron) u Electron (Lepton) High Energy Physics Structure of Matter 10-14m 10-9m 10-10m 10-15m <10-19m 10-2m Condensed matter/Nano-Science/Chemistry protons, neutrons, mesons, etc. p,W,L... top, bottom, charm, strange, up, down Atomic Physics Nuclear Physics <10-18m PHYS 3446, Fall 2006 Jae Yu
Theory for Microscopic Scale, QM • Difficult to describe Small scale phenom. w/ just CM and EM • The study of atomic structure led toquantum mechanics • Long range EM force is responsible for holding atoms together (why ?) • Yet sufficiently weak for QM to estimate properties of atoms reliably • In Nucleus regime, the simple Coulomb force does not work. Why? • The force in nucleus holds positively charged particles together • The known forces in nature • Strong ~ 1 • Electro-magnetic ~ 10-2 • Weak ~ 10-5 • Gravitational ~ 10-38 PHYS 3446, Fall 2006 Jae Yu
Evolution of Atomic Models Cathode ray tube • 1803: Dalton’s billiard ball model • 1897: J.J. Thompson Discovered electrons • Built on all the work w/ cathode tubes • Called corpuscles • Made a bold claim that these make up atoms • Measured m/e ratio • 1904: J.J. Thompson Proposed a “plum pudding” model of atoms • Negatively charged electrons embedded in a uniformly distributed positive charge Thompson’s tubes PHYS 3446, Fall 2006 Jae Yu
History of Atomic Models cnt’d • 1911: Geiger and Marsden with Rutherford performed a scattering experiment with alpha particles shot on a thin gold foil PHYS 3446, Fall 2006 Jae Yu
History of Atomic Models cnt’d • 1912: Rutherford’s planetary model, an atomic model with a positively charged heavy core surrounded by circling electrons • Deficiency of instability. Why? • The electrons will eventually get pulled onto the nucleus, destroying the atom PHYS 3446, Fall 2006 Jae Yu
History of Atomic Models cnt’d • 1913: Neils Bohr proposed the Orbit Model, where electrons occupy well quantified orbits • Electrons can only transition to pre-defined orbits PHYS 3446, Fall 2006 Jae Yu
History of Atomic Models cnt’d • 1926: Schrödinger and de Broglie proposed the Electron Cloud Model based on quantum mechanics PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering • A fixed target experiment with alpha particle as projectile shot on thin gold foil • Alpha particle’s energy is low Speed is well below 0.1c (non-relativistic) • An elastic scattering of the particles • What are the conserved quantities in an elastic scattering? • Momentum • Kinetic Energy PHYS 3446, Fall 2006 Jae Yu
ma ma q f mt Elastic Scattering After Collisions mt • From momentum conservation • From kinetic energy conservation • From these two, we obtain PHYS 3446, Fall 2006 Jae Yu
Analysis Case I • If mt<<ma, • left-hand side becomes positive • va and vt must be in the same direction • Using the actual masses • and • We obtain • If mt=me, then mt/ma~10-4. • Thus, pe/pa0<10-4. • Change of momentum of alpha particle is negligible PHYS 3446, Fall 2006 Jae Yu
Analysis Case II • If mt>>ma, • left-hand side of the above becomes negative • va and vt is opposite direction • Using the actual masses • and • We obtain • If mt=mAu, then mt/ma~50. • Thus, pe/pa0~2pa0. • Change of momentum of alpha particle is large • a particle can even recoil PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering with EM Force 1 • Let’s take into account only the EM force between the a and the atom • Coulomb force is a central force, so a conservative force • Coulomb potential between particles with Ze and Z’e electrical charge separated by distance r is • Since the total energy is conserved, PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering with EM Force 2 • The distance vector r is always the same direction as the force throughout the entire motion, so the net torque (rxF) is 0. • Since there is no net torque, the angular momentum (l=rxp) is conserved. The magnitude of the angular momentum is l=mvb. Impact parameter • From the energy relation, we obtain • From the definition of angular momentum, we obtain an equation of motion • From energy conservation, we obtain another equation of motion Centrifugal barrier Effective potential PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering with EM Force 3 • Rearranging the terms for approach, we obtain • and • Integrating this from r0 to infinity gives the angular distribution of the outgoing alpha particle Distance of closest approach PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering with EM Force 4 • What happens at the DCA? • Kinetic energy reduces to 0. • The incident alpha could turn around and accelerate • We can obtain • This allows us to determine DCA for a given potential and c0. • Define scattering angle q as the changes in the asymptotic angles of the trajectory, we obtain PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering with EM Force 5 • For a Coulomb potential • DCA can be obtained for the given impact parameter b, • And the angular distribution becomes PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering with EM Force 6 • Replace the variable 1/r=x, and performing the integration, we obtain • This can be rewritten • Solving this for b, we obtain PHYS 3446, Fall 2006 Jae Yu
Rutherford Scattering with EM Force 7 • From the solution for b, we can learn the following • For fixed b, E and Z’ • The scattering is larger for a larger value of Z. • Makes perfect sense since Coulomb potential is stronger with larger Z. • Results in larger deflection. • For fixed b, Z and Z’ • The scattering angle is larger when E is smaller. • If particle has low energy, its velocity is smaller • Spends more time in the potential, suffering greater deflection • For fixed Z, Z’, and E • The scattering angle is larger for smaller impact parameter b • Makes perfect sense also, since as the incident particle is closer to the nucleus, it feels stronger Coulomb force. PHYS 3446, Fall 2006 Jae Yu
Assignments • Compute the masses of electron, proton and alpha particles in MeV/c2, using E=mc2. • Need to look up masses of electrons, protons and alpha particles in kg. • Compute the gravitational and the Coulomb forces between two protons separated by 10-10m and compare their strengths • Derive the following equations in your book: • Eq. # 1.3, 1.17, 1.32 • Must show detailed work and accompany explanations • These assignments are due next Wednesday, Sept. 6. PHYS 3446, Fall 2006 Jae Yu