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P 1 P 2 : Parental strains. Homozygous at all loci, but differing in phenotype.

Recombinant Inbred Strains: Step 1: Initial Mendelian Cross. P 1. P 2. P 1 P 2 : Parental strains. Homozygous at all loci, but differing in phenotype. P 1 P 2 : Parental strains. Homozygous at all loci, but differing in phenotype. F 1 : First filial.

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P 1 P 2 : Parental strains. Homozygous at all loci, but differing in phenotype.

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  1. Recombinant Inbred Strains: Step 1: Initial Mendelian Cross P1 P2 P1P2: Parental strains. Homozygous at all loci,but differing in phenotype. P1P2: Parental strains. Homozygous at all loci,but differing in phenotype. F1: First filial. Heterozygous at all loci.Breed with one another to get F2. F1: First filial. Heterozygous at all loci.Breed with one another to get F2. F2: Second filial. Recombination in F1gametes gives a mixtureof P1 and P2 chromosome sections.

  2. Recombinant Inbred Strains: Step 2: Sib-matings F2 × × × × F3 × × × × × × × × FA Lot

  3. Recombinant Inbred Strains: Phenomenon 1: Recombination will breakup the red versus blue segments. Note how thereis more red/blue combinations in F3 than in F2. F2 × × × × F3 × × × ×

  4. Recombinant Inbred Strains: Phenomenon 2: Sib matings increase homozygosity. After a large number of generations (20 is close to “large”), one creates inbred strains that are identical at all loci. × × × × F3 × × × × FA Lot

  5. Common Sense Explanation: Recombination breaks up the red versus blue areas. But within a line of sib matings, the SAME red/blue combinations are transmitted and, after a long time, become homozygous..

  6. Recombinant Inbred Strains: Linkage Analysis At each locus, ½ of the strains should be rr and the other 1/2will be bb. Do a t-test using phenotypic scores as thedependent variable and genotype ( rr versus bb) as the group variable.If the test is significant, then that gene (or more likely, a geneclose to the genotyped locus) influences the phenotype. A more complicated approach would use haplotypes.

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