1 / 2

Max And Amy’s Math Thing

Max And Amy’s Math Thing. Widget=x 1200 > x > 500 Gadget=y 1400 > y > 700 x+y > 2300. Situation:.

caldwell-porter
Download Presentation

Max And Amy’s Math Thing

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Max And Amy’s Math Thing Widget=x 1200>x>500 Gadget=y 1400>y>700 x+y>2300 Situation: A manufacturer makes widgets and gadgets at least 500 widgets and 700 gadgets are needed to meet the minimum daily demands. A machine can produce 1200 widgets and 1400 gadgets per day. If the company sells widgets for $ 0.40 and gadgets for $ 0.50 each, how many of each item should be produced for maximum income? Profit= $0.40x+$0.50y $830= .40(1200)+.50(700) $1030=.40(1200)+.50(1100) $1060=.40(900)+.50(1400) $550=.40(500)+.50(700) $900=.40(500)+.50(1400)

  2. Summary To find the maximum profit of widgets and gadgets we began by listing all constraints that we found. After listing constraints, we graphed the constraints and found the feasible region and important points. Once we found this, we substituted the x and the y values in the objective function to find the maximum profit and the minimum profit. We discovered that when x is 900 and y is 1400, the profit will be the most.

More Related