1 / 7

Problem Set 4, Number 3

Problem Set 4, Number 3. Dan Heflin. The Problem at Hand. Well, to begin, let us try and find an a that fits the description we need. a = ?. So, these curves intersect at every value for which , and . But, we will look at , since it is the smaller value.

callia
Download Presentation

Problem Set 4, Number 3

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Problem Set 4, Number 3 Dan Heflin

  2. The Problem at Hand Well, to begin, let us try and find an a that fits the description we need.

  3. a = ? • So, these curves intersect at every value for which , and . But, we will look at , since it is the smaller value. • So, , since we need the smallest positive value where the curves next intersect after 0.

  4. Graphs

  5. Combined Graph 0

  6. Now We Must Integrate! • Well, now that we know the top and bottom curve, all we must simply do is integrate.

  7. Final Answer….. • After plugging in our values, we get • Mathematica comes up with the same answer!! =

More Related