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0. Chemical Equilibrium. Chemistry, The Central Science , 10th edition Theodore L. Brown, H. Eugene LeMay, Jr., and Bruce E. Bursten. Donna Narsavage Heald Siena College Loudonville, NY 2006, Prentice-Hall. 2NO (g) + O 2 (g) 2NO 2 (g). 0.
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0 Chemical Equilibrium Chemistry, The Central Science, 10th edition Theodore L. Brown, H. Eugene LeMay, Jr., and Bruce E. Bursten Donna Narsavage Heald Siena College Loudonville, NY 2006, Prentice-Hall
2NO (g) + O2 (g) 2NO2 (g) 0 What is Kp in terms of Kc for the following reaction ? • Kp = KcRT • Kp = Kc/RT • Kp = KcR/T • Kp = Kc • Kp = Kc/(RT)2
2NO (g) + O2 (g) 2NO2 (g) 0 What is Kp in terms of Kc for the following reaction ? • Kp = KcRT • Kp = Kc/RT • Kp = KcR/T • Kp = Kc • Kp = Kc/(RT)2
P4 (s) + 6Cl2 (g) 4PCl3 (l) 0 What is the correct equilibrium constant expression for the reaction:
P4 (s) + 6Cl2 (g) 4PCl3 (l) 0 What is the correct equilibrium constant expression for the reaction:
2NO (g) + O2 (g)2NO2 (g) NO NO2 0 Which accurately reflects the changes in concentration that will occur if O2 is added to disturb the equilibrium?
2NO (g) + O2 (g)2NO2 (g) NO NO2 0 Which accurately reflects the changes in concentration that will occur if O2 is added to disturb the equilibrium?
PCl3 (g) + Cl2 (g) PCl5 (g) DH° = -87.9 kJ/mol 0 Which of the following will result in an equilibrium shift to the right? • Increase temperature/increase volume • Increase temperature/decrease volume • Decrease temperature/increase volume • Decrease temperature/decrease volume • None of the above PCl5
PCl3 (g) + Cl2 (g) PCl5 (g) DH° = -87.9 kJ/mol 0 Which of the following will result in an equilibrium shift to the right? • Increase temperature/increase volume • Increase temperature/decrease volume • Decrease temperature/increase volume • Decrease temperature/decrease volume • None of the above PCl5
2CO(g) + O2(g) 2CO2(g) Kc = 5.0 x 1018 at 25 °C CO2(g) CO(g) + 1/2 O2(g) Kc = ?? at 25 °C 0 What is the value of Kc for the reaction? • Kc= 1/(5.0 x 1018)1/2 • Kc= 1/(2.5 x 1018) • Kc= -(5.0 x 1018)/2 • Kc= -(5.0 x 1018)1/2 • Kc= 2/(5.0 x 1018)1/2
2CO(g) + O2(g) 2CO2(g) Kc = 5.0 x 1018 at 25 °C CO2(g) CO(g) + 1/2 O2(g) Kc = ?? at 25 °C 0 What is the value of Kc for the reaction? • Kc= 1/(5.0 x 1018)1/2 • Kc= 1/(2.5 x 1018) • Kc= -(5.0 x 1018)/2 • Kc= -(5.0 x 1018)1/2 • Kc= 2/(5.0 x 1018)1/2