170 likes | 292 Views
FORCES IN FLIGHT. Weight (Gravity) Lift Drag Thrust. Weight. A force that is caused by the gravitational attraction of the Earth Depends upon all of the parts of the airplane, plus fuel, plus payload on board (freight, people, baggage, etc.) Distributed throughout the plane
E N D
FORCES IN FLIGHT Weight (Gravity) Lift Drag Thrust
Weight • A force that is caused by the gravitational attraction of the Earth • Depends upon all of the parts of the airplane, plus fuel, plus payload on board (freight, people, baggage, etc.) • Distributed throughout the plane • The airplane moves around a single point known as center of gravity
Why is weight so important? • Flying encompasses 2 major problems: • Overcoming the weight of the plane • Controlling the object in flight • Weight changes constantly as fuel is consumed • Pilot must constantly adjust controls and fuel distribution or keep it “trimmed”
Lift • In order to overcome weight force, planes must generate opposing force of lift • Created by the motion of the plane through the air • Perpendicular to the flight motion • Magnitude of lift is dependent on shape size and velocity of the aircraft
How is most lift generated? • Most lift is produced from the wings • Distribution of lift around aircraft is vital to solving problem of control • Acts through a center of pressure (avg location of pressure on the wing) • Roll, pitch and yaw are used in combination with the aerodynamic surfaces to control plane
Drag • Considered a resistance force • Due to air resisting the motion of the aircraft • Directed along and opposed to the direction of flight • Shape of aircraft, “stickiness” of the air and velocity affect drag
Thrust • Mechanical force created by the engines to move the aircraft through the air • In order to overcome drag, propulsion systems are used to generate thrust • Magnitude is dependent on type of engine, number of engines and the throttle setting
How does thrust work? • It can be confusing to remember that thrust is a reaction to hot gas rushing out the nozzle of the engine • The hot gas goes out the back, but the thrust pushes toward the front • This action – reaction is explained through Newton’s 3rdlaw of motion • Examples http://www.grc.nasa.gov/WWW/K-12/WindTunnel/Activities/third_law_motion.html
Newton’s 1st Law of Motion • An object at rest will tend to stay at rest unless acted upon by unbalanced force • An object in motion will stay in motion with the same speed and direction unless acted upon by an unbalanced force • That resistance to change is known as inertia. • Known as the law of inertia
Practice with 1st Law • Answer the following: External force or no external force • An F-9 is flying at 250mph at 30000 ft • The F-9 turns southwest at 250mph • The F-9 increases its speed to 275mph • The F-9 drops to 25000ft at same speed & direction
Answers: • An F-9 is flying at 250mph at 30000 ft No external force • The F-9 turns southwest at 250mph External force (direction/velocity change) • The F-9 increases its speed to 275mph External force (speed/velocity change) • The F-9 drops to 25000ft at same speed & direction External force (gravity)
Newton’s 2nd Law of Motion • Acceleration of an object is dependent upon two variables: net force acting on the object and the mass of the object • Formula: f = m x a • This can be used when determining excess thrust of an airplane
Determining Excess Thrust • Excess thrust = Thrust – Drag • Fex= T – D • Fex = m * a (Newton’s 2nd law) • a = Fex/ m • So, a = T-D/ m Fex = Excess thrust a = accelleration m = mass T = thrust D = drag
2nd Law Practice Problem #1 • An airplane has a mass of 150,000 kg and it is moving at a rate of 400 mi/min2. • What is the excess thrust currently? • Remember Fex = m * a
Answer Problem #1 • An airplane has a mass of 150,000 kg and it is moving at a rate of 400 mi/min2. • F= m * a • F = 150,000kg * 400 mi/min2 • F = 6,000,000 kg*mi/min2
Practice Problem # 2 • An small airplane has an excess thrust of 4,250,000 kg*m/s2 and has a mass of 8500 kg. • What is the acceleration of the plane? • Remember a = Fex/m
Answer Problem #2 • An small airplane has an excess thrust of 4,250,000 kg*m/s2 and has a mass of 8500 kg. • a = F/m • a = 4,250,000kg*m/s2/ 8500 kg • a = 500 m/s2