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Newton’s 2 nd Law Lab

Newton’s 2 nd Law Lab. Marcy Road 11/13/08. Newton’s 2 nd Law Data. Trial #1 Vi=d/t Vf=d/t Vi=.200/.521 Vf=.200/.209 Vi=.384 m/s Vf=.957 m/s Vf^2=Vi^2+2ad .957^2=.384^2+2(a)1.515 .915849=.147456+3.03 .76839=3.03a .254 m/s/s=a. Trial #1 Continued… w=m*g f=m*a

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Newton’s 2 nd Law Lab

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  1. Newton’s 2nd Law Lab Marcy Road 11/13/08

  2. Newton’s 2nd Law Data

  3. Trial #1 Vi=d/t Vf=d/t Vi=.200/.521 Vf=.200/.209 Vi=.384 m/s Vf=.957 m/s Vf^2=Vi^2+2ad .957^2=.384^2+2(a)1.515 .915849=.147456+3.03 .76839=3.03a .254 m/s/s=a

  4. Trial #1 Continued… w=m*g f=m*a w=.600*9.81 5.886=m*.254 w=5.886 N 23.173 kg=m %diff=act.-exp./act *100 %diff=1.820-23.173/1.820*100 %diff=21.353/1.820*100 %diff=11.73241758*100 %diff=1,173%

  5. Trial #2 Vi=d/t Vf=d/t Vi=.200/.341 Vf=.200/.209 Vi=.587 m/s Vf=1.639 m/s Vf^2=Vi^2+2ad 1.639^2=.587^2+2(a)1.515 2.686321=.344569+3.03a 2.341752=3.03a .773 m/s/s=a

  6. Trial #2 Continued… w=m*g f=m*a w=.800*9.81 7.848=m*.773 w=7.848 N 10.765 kg=m %diff=act.-exp/act*100 %diff=1.820-10.765/1.820*100 %diff=8.945/1.820*100 %diff=4.914835165*100 %diff=491%

  7. Trial #3 Vi=d/t Vf=d/t Vi=.200/.269 Vf=.200/.094 Vi=.743 m/s Vf=2.128 m/s Vf^2=Vi^2+2ad 2.128^2=.743^2+2(a)1.515 4.528384=.552049+3.03a 3.976335=3.03a 1.312 m/s/s=a

  8. Trial #3 Continued… w=m*g f=m*a w=1.000*9.81 9.81=m*1.312 w=9.81 N 7.477 kg=m %diff=act.-exp./act.*100 %diff=1.820-7.477/1.820*100 %diff=5.657/1.820*100 %diff=3.108241758*100 %diff=311%

  9. Diagram ceiling pulley weight string gate #2 gate #1 sled board pulley counter floor

  10. Questions • Newton’s 2nd Law states that when an unbalanced fore acts on an object, the object is accelerated in the direction of the force. • We used Newton’s 2nd Law to find the mass of the cart by creating an unbalanced force on the cart and measured the acceleration. • The y-values are the force applied, the x-values are the acceleration and the plotted dots or the slope are the mass. • The force needed to overcome the friction on the cart is the y-intercept, 4.9576 N.

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