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Physics Problem Solving Chapter 5.1 Solutions

This text provides solutions to selected problems from Chapter 5.1 in physics, covering concepts like forces, Newton's laws, and acceleration calculations. Detailed explanations are given for each problem to aid understanding.

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Physics Problem Solving Chapter 5.1 Solutions

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  1. Selected Problems from Chapter 5

  2. 1) T ma mg F=ma mg-T=ma T=m(g-a) T=700(9.8-3.8)= 4200 = 4.2 kN up

  3. 2) N a N a Fx Fy F=20 N mg mg

  4. 3) 36N A+B 36N NAB A M=mA+mB=24 kg F=Ma a=F/M=36/24=1.5 m/s2 F-NAB=mAa NAB=F-mAa=36-4x1.5=30 N

  5. 4) a a F C F T1 A,B&C F-T1=ma (for block C) T1=F-ma=F-m(F/3m)=2F/3 (consider A,B,C as one object M=3m) F=3ma hence, a=F/3m

  6. 5) T T a a a a m1g m2g T-m1g=m1a (1) m2g-T=m2a (2) add (1) & (2): (m2-m1)g=(m1+m2)a a =(m2-m1)g/(m1+m2)=(2/6)x9.80= 3.27 m/s2

  7. 6) y-axis N a F=40 N F=40 N a x-axis mgsin30o mgcos30o 30o 30o 30o Along the x-axis: mgsin30o-F=ma m(gsin30o-a)=F m=F/(gsin30o-a)=40/(9.80x0.5-2.0)=14 kg N mg mg

  8. 7) a a a a N N T T a 30o T W1=m1g m2g Wx m2g-T=m2a (2) T-Wx=m1a (1) Wy Wx=W1sin30o Wy=W1cos30o add (1) & (2): and substitute to get the answer: a = 0.69 m/s2down

  9. Continued……

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