1 / 8

Graph a linear equation

Graph a linear equation. Solve for y so the equation looks like y = mx + b. Graph: 2x – 3y = -12 . - 3y = -2x – 12 Subtract 2x to both sides. y = x + 4 Divide by –3 to both sides. Now we can choose values for x to find values for y. X Y. 6. 3. y = (3) + 4. y = 2 + 4.

carolinaarnett
Download Presentation

Graph a linear equation

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Graph a linear equation Solve for y so the equation looks like y = mx + b Graph: 2x – 3y = -12 - 3y = -2x – 12 Subtract 2x to both sides. y = x + 4 Divide by –3 to both sides. Now we can choose values for x to find values for y. X Y 6 3 y = (3) + 4 y = 2 + 4 y = 6 4 0 y = (0) + 4 y = 4 -3 2 PLOT y = (-3) + 4 y = -2 + 4 y = 2 NOW GRAPH A LINE

  2. Graph a linear equation Solve for y so the equation looks like y = mx + b Graph: 3x – 4y = 8 - 4y = -3x + 8 Subtract 3x to both sides. y = x – 2 Divide by –4 to both sides. Now we can choose values for x to find values for y. X Y 1 4 y = (4) -2 y = 3 - 2 y = 1 -2 0 y = (0) - 2 y = -2 -4 -5 PLOT y = (-4) - 2 y = -3 - 2 y = -5 NOW GRAPH A LINE

  3. Graph a linear equation Missing a y term, so solve for x Graph: 3x = 6 X = 2 Divide by 3 Now we can graph a line in which the value for x is 2 in all coordinates. Notice the line is vertical because every coordinate on the line has an x coordinate of 2. (2, 6) (2, 0) (2, -5)

  4. Graph a linear equation Missing a x term, so solve for y Graph: -4y = 12 Y = -3 Divide by -4 Now we can graph a line in which the value for y is -4 in all coordinates. Notice the line is horizontal because every coordinate on the line has a y coordinate of -4. (-3, -4) (0, -4) (3, -4)

  5. Graph a linear equation using x and y intercepts. Let x = 0 Graph: 2x – 3y = -12 Now let y = 0 2(0) – 3y = -12 2x – 3(0) = -12 2x – 0 = -12 0 - 3y = -12 2x = -12 -3y = -12 x = -6 y = 4 x intercept is (-6, 0) y intercept is (0, 4) PLOT NOW GRAPH A LINE

  6. Graph a linear equation using x and y intercepts. Let x = 0 Graph: -5x + 3y = -15 Now let y = 0 -5(0) + 3y = -15 -5x + 3(0) = -15 -5x + 0 = -15 0 + 3y = -15 -5x = -15 3y = -15 x = 3 y = -5 x intercept is (3, 0) y intercept is (0, -5) PLOT NOW GRAPH A LINE

  7. Graph a linear equation, by using y intercept and slope. Solve for y so the equation looks like y = mx + b Graph: 2x – 3y = -12 - 3y = -2x – 12 Subtract 2x to both sides. y = x + 4 Divide by –3 to both sides. Now the equation is in y = mx + b form called slope y-intercept form. m is the slope of the line and b is the y-intercept (0, 4) Now plot the y-intercept (0, 4) The slope of the line is so from the coordinate (0, 4) go up 2 lines, then move right 3 lines and plot a 2nd point. UP 2 RIGHT 3 NOW GRAPH A LINE

  8. Graph a line given one point and the slope of the line. Graph the line that passes through the point (-4, 5) and has a slope of . Plot the point (-4, 5) Now from the point (-4, 5) the slope is , so go down 3 lines and then right 5 lines. DOWN 3 RIGHT 5 Now graph the line

More Related