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Warm-up Day of 8.1, 8.2, 9.1 and 9.2 Review. Answer to H.W. Problem E#17.
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Answer to H.W. Problem E#17 Step 1: The amount of water in the bottles is normally distributed. A graph of the sample is unimodal and skewed right. The bottles selected for the sample were randomly selected. The 10 bottles selected should be less than 10% of the bottles produced that day. The conditions are met to perform a one sample t test. Step 2: Ho: μ = 16 oz HA = μ ≠ 16 oz The null hypothesis states that the bottles should contain 16 oz. The alternate hypothesis states that the bottles do not contain 16 oz.
Step 3 and 4 of E #17 In conclusion I do not have sufficient information to reject the null hypothesis. 1/3 of the bottles fall below or above 1 S.E. which is 0.026 oz away from the mean. It is plausible that the mean weight of the bottle is 16 oz.
A.P. Statistics Exam Information on Timing I would not say "plenty of time". Adequate time. Students need to move through the questions promptly, reading carefully, and not wasting time on the ones they don't see how to do. Come back to those later. They should feel pretty ok with the MC. Time management on the FR is more critical. Chances are they will not have enough time to answer every part of every question. They need to find the questions they can do well on, and do them. And they need to invest some time in the investigative task, as that counts more. Better to run out of time struggling with something you weren't going to score well on anyway than to leave a question you could have done unanswered. To that end, I recommend to my students that they start the FR by simply reading every question. Pick out the 3 questions they feel most confident about and do those first. Then tackle the investigative task and get something done there. When that bogs down, go back to the other 2 they skipped at first and do as much as they can. With any remaining time, take another crack at the task. The goal is to feel not that "I ran out of time; with another 20 minutes I could have done more." but that "I finished everything I knew how to do; another 20 minutes wouldn't have made much difference."
8.1, 8.2, 9.1 and 9.2 Review out of the textbook 8.1 E#7 and #8; 8.2 P#37, E #25*,#26*,#27 9.1 E #5; 9.2 E#24, #31* * indicates multiple choice problem Ch.8 level of confidence(capture rate), margin of error significance test for a proportion, statistical significance, null hypothesis, alternate hypothesis, test statistic, p-value, critical values, level of significance, type 1 error, type 2 error, power of a test, one-sided, two-sided test Ch.9 Degrees of freedom, Sampling distribution for s, t-table, t-test, t-distribution, significance test for the mean. (17 terms –Ch. 8, 6 terms –Ch 9 = 23 terms at 1pt each = 23pts) Notes: 8.1, 8.1 (Day 2), 8.2, 8.2 (Day 2), 8.2 (Errors), 9.1, 9.2 ( 7 notes w/ Warm-ups 11 pts each = 77 pts) (3 pt warm-up 8 pts notes = 11 pts) 77 pts + 23 pts = 100 for Ntbk
8.1 E#8; 8.2 E#26* 9.2 E#24 8.1 E#8 The poll was not described as random. 885 adults is less than 10% of the adult U.S. population. 885 (0.4) > 10 and 885(0.6)> 10 so the success/failure condition is also met. 8.2 E#26 C … Because of “must” it should be likely 9.2 E#24 a. Ho: u = 650 HA: u < 650 T-Test p-value =0.3305 t = -0.448. The student’s assumption that the rents are at or above $650 can not be rejected. However, since the sample was not random, you would have to question the results. b. The newspaper is looking into whether then mean rent was either at $500 or not $500. Ho: u = 500 HA: u≠500. The p-value is 0.0007. If it is true that the true mean is $500, there is a 7 in 10000 of getting a mean rent of $500 with as sample size of 15.
