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Class Presentation Outline for Projectile Motion. Created for CVCA Physics By Dick Heckathorn 28 November 2K+4 Needs updating from short one. Table of Contents. 3 A projectile is 4 Dropping an object 5 Laser Disk A: 41, 42, 43, 44 7 Dropping an Object 9 Throwing Horizontally
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Class Presentation Outline forProjectile Motion Created for CVCA Physics By Dick Heckathorn 28 November 2K+4 Needs updating from short one
Table of Contents • 3 A projectile is • 4 Dropping an object • 5 Laser Disk A: 41, 42, 43, 44 • 7 Dropping an Object • 9 Throwing Horizontally • 11 Dropping a Super Ball • 12 Laser Disk B: 11, 12, 13, 14, 15 • 22 Problem: Thrown Horizontal • 24 Problem: Horizontal Up • 28 Problem: Horizontal Down p 205 # 45 • 31 Assumptions
A projectile is: • Any object that moves through the air or through space acted only on by gravity (and air resistance if any). • We will ignore air resistance unless information relative to it is stated.
Dropping an object. • The only force acting on the object is the pull of the earth acting on it in a down direction. • This causes the object to accelerate at the rate of 9.8 m/s2 in the same downward direction.
A 41 Free Fall Ride • Falling on Demon Drop • Accelerometer Shown • Always parallel to tracks
A 42, 43 Falling Bowling Ball • Bowling ball released from 4 m A 44 Falling “Down Under” in Australia • Object dropped in both • New York and Australia
Droping an object • To analyze the motion one uses the five kinematic equations with the variables: a, vi , vf , d and t. • Remember that you can use one of the calculator programs to find any two variables given the other three.
Coffee Filter Investigation • Handout: #13 Air Resistance • Motion Sensor on Ceiling • Computer • Lab Pro • TI-83+ • Printer – Online & Epson FX
Throwing an Object Horizontal • If one assumes that there is no gravitational force of the earth on the object… • it will travel in a horizontal direction with a constant velocity. • Relative variables are: vh, dh, and t.
Throwing an Object Horizontal • It we deal with reality, there is the force of gravity acting on the object. • How does this force affect the horizontal component of the motion of the object?
Throwing an Object Horizontal • Demo: Super Ball • We can see that the force of gravity acting on the ball does not affect the horizontal motion which is at right angles to the direction of the force of gravity.
B 11 Projectile Motion • Ball was projected horizontally, another dropped straight down • Later, horizontally lines drawn • Old PSSC – large white balls
B 12 Projectile Motion • Ball shot horizontally from crossbow as a target ball is dropped horizontally. Both originally aligned horizontal. • Old PSSC – large white balls
B 13 Projectile Motion • Ball shot at an upward angle from crossbow as a target ball is dropped horizontally. • Old PSSC – large white balls
B 14 Projectile Motion • Ping pong balls glued to plexiglas sheet at equal time intervals • Old PSSC – Professor Hume
B 15a Projectile Motion • Air table is tilted so pucks respond to “diluted gravity”. • One shot horizontal, one dropped. • Frame 3573
B 15b Projectile Motion • Frame 3914 • Determine range of angle • vs • angle of shot.
B 15c Projectile Motion • Frame 4385 • Shot-putter
Throwing an Object Horizontal • We have seen that: • the horizontal and vertical components do not affect each other • the vertical motion is that of free fall.
Throwing an Object Horizontal • Each component can be • analyzed independent of each other. • We do so according to the following:
Throwing an Object Horizontal • Vertical • a • vi • vf • dv • t • Horizontal • dh • vh • t
Problem 1 • An object is thrown horizontally at 27 m/s from the edge of a cliff which is 40 m above the ground. • How long does it take to reach the ground? • What is the range of the ball? (Horizontal distance) • With what velocity did it strike the ground?
We are given and know: How long to reach the ground? • Vertical • a = • vi = • vf = • dv = • t = • Horizontal • dh = • vh = • t = 9.8 m/s2↓ 77.2 m 0 m/s 27 m/s 28 m/s ↓ 2.86 s 40 m ↓ 2.86 s The velocity as it strikes the ground: ? The value for vf is: ? Solve for ‘t’ by: ? 38.9 m/s Solve for dh : ? H 46.0o D
Problem 2 • An object is thrown with a speed of 725 m/s at an angle of H 60o U. • How long does it take to reach the ground? • What is the range of the ball? (Horizontal distance) • With what velocity did it strike the ground?
First find the horizontal and vertical component of the initial velocity. • 730 m/s • 632 m/s 60o • 365 m/s
We are given and know: • Vertical • a = • vi = • vf = • dv = • t = • Horizontal • dh = • vh = • t = 9.8 m/s2↓ 47085 m 632 m/s ↑ 365 m/s 632 m/s ↓ 0 m/s no 129 s no 64.5 s 20379 m ↑ 64.5 s The value for dv is: ? Solve for t by: ? 730 m/s Solve for dh is: ? The velocity as it strikes the ground: ? H 60.0o D
OR • Vertical • a = • vi = • vf = • dv = • t = • Horizontal • dh = • vh = • t = 9.8 m/s2↓ 47085 m 632 m/s ↑ 365 m/s 632 m/s ↓ 129 s 20379 m ↑ 129 s The value for dv is: ? Solve for t by: ? 730 m/s Solve for dh is: ? The velocity as it strikes the ground: ? H 60.0o D
Problem 3 • A bomber, diving at an angle of 53o with the vertical, releases a bomb at an altitude of 730 m. The bomb hits the ground 5.0 sec after being released.
Problem 3 First find the horizontal and vertical component velocities of the bomb. • 161.2 m/s 53o • 121.5 m/s • 202 m/s
We are given and know: • Vertical • a = • vi = • vf = • dv = • t = • Horizontal • dh = • vh = • t = 9.8 m/s2↓ 806 m 121.5 m/s ↓ 161.2 m/s 170.5 m/s↓ 5.0 s 730 m ↓ 5.0 s The velocity as it strikes the ground: ? The value for vf is: ? ___ m/s The value for dh is: ? The value for t is: ? H ____ D
Assumptions Projectile Motion • 1. The effect air resistance has been ignored. • Air resistance will shorten the horizontal distance a ball will go. • A baseball projected to go • 120-m will only go 71.4-m.
Assumptions Projectile Motion • 2. The acceleration due to gravity is constant. • We will find that the acceleration due to gravity varies inversely proportional to the square of the distance from the center of the earth.
Assumptions Projectile Motion • 3. The earth is assumed to be flat as the circumference is very large. • Thus for large horizontal distances the calculated distance is not exactly correct.
Assumptions Projectile Motion • 4. Projectile remains in same vertical plane during flight. • A projectile launched directly north will not follow the longitudinal line from which it is launched due to the rotation of the earth on its axis.
Need for a computer • When sending a rocket to the moon, constant calculations are needed to update the corrections need to get the rocket to the moon. • When the computers went down on Apollo 13, there was nothing to update the data.
Apollo 13 Video • Scene when aligning up spacecraft to enter earth’s atmosphere at the correct angle.
Article • Notes from the Military