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CH3Br, 161109 C, C* and C** dissociation formation channels vs C+ spectra Explanation for enhanced C+ Rydberg state spectra in the 80600 - 80950 cm-1 region. Agust,heima,...Nov09/CH3Br-Overall +mass-041109km-141109ak.pxp Agust,www,.... Nov09/PPT-161109ak.ppt.
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CH3Br, 161109 C, C* and C** dissociation formation channels vs C+ spectra Explanation for enhanced C+ Rydberg state spectra in the 80600 - 80950 cm-1 region Agust,heima,...Nov09/CH3Br-Overall +mass-041109km-141109ak.pxp Agust,www,.... Nov09/PPT-161109ak.ppt
Agust,heima,...Nov09/CH3Br-Overall +mass-041109km-141109ak.pxp: H2 + C* + HBr Predictions2s22p4p(1D2): 71577.2 2s22p5p: 2s22p6p: 2s22p4p(1S0): 72059.1 H2 + C + HBr ATH! 2hv
agust, heima, ....Nov09/CH3Br-Overall +mass-041109km-121109ak.pxp: (1/2)4f;0+ (3/2)5f;1/0 (1/2)4f;1 (3/2)6d;2 (1/2)5d;2 (1/2)5d;0 (3/2)6d;0 (1/2)4f;1 (1/2)4f;0+ (3/2)5f;1/0 (3/2)6d;0 (1/2)5d;0 C+
We observe enhanced Rydberg state structure in the spectra region 80600 - 80950 cm-1 by recording C+.This could be for two reasons:1) -because we switch from three photon ionization of C*(1D) (formed after dissociation of CH3Br*(Rydberg state) to form H2 + C*(1D) + HBr) to two photon ionization.or2) formation of C**(2s22p2; 1S) due to opening of yet another dissociation channel:CH3Br* -> H2 + C**(2s22p2; 1S) + HBr See relevant energetics in next slides:
Ca = 70000 + 80625.27= 150625 cm-1 1) C++H2+HBr+ e- 150k C**(1D2)+H2+HBr 130k 90817.9 -10192.63= 80625.27 cm-1 IP(C) = 90817.9 (see notes 240809;1)& http://www.nist.gov/srd/nsrds/NSRDS-NBS34.pdf 80600 cm-1 CH3Br* 80k C*(1D2)+H2+HBrca 70000 70k 10192.63 (NIST) C (3PJ)+ H2+HBrca < 60000(?) 40k 40300 10k CH3Br
2) (alternatively) Ca = 69169.89 + 80600= 149770 cm-1 C++H2+HBr+ e- 150k C**(1D2)+H2+HBr 130k IP(C) = 90817.9 (see notes 240809;1)& http://www.nist.gov/srd/nsrds/NSRDS-NBS34.pdf 90817.9 -21648.01= 69169.89 cm-1 C*(1S)+H2+HBrca 80600 80600 cm-1 CH3Br* 80k C*(1D2)+H2+HBrca 69144.63 21 648.01 (NIST) 70k 10192.63 (NIST) C (3PJ)+ H2+HBrca 58952(?) NB:AB comes up with a value of 704 kJ Mol-1 / 58840 cm-1 704 = 0+711.19-28.6-(-21.3) for 0 K(e-mail: 041109) I obtain 709.7 kJmol-1/59329 cm-1 for DE obtained for DHf standard values (seehttp://www3.hi.is/~agust/rannsoknir/rempi/ch3br/Nov09/PPT-151109ak.ppt) 40k 40300 10k CH3Br