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Circular measure. Definition of p Definition of radians. Unit 4:Mathematics. Aims Introduce radians and circular theorem. Objectives Identify parts of a circle and calculate triangles within a circle. Calculate circular and segment measures. Re-Call.
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Circular measure Definition of p Definition of radians
Unit 4:Mathematics Aims • Introduce radians and circular theorem. Objectives • Identify parts of a circle and calculate triangles within a circle. • Calculate circular and segment measures.
Re-Call • sine x = (side opposite x)/hypotenuse cosine x = (side adjacent x)/hypotenuse tangent x =(side opposite x)/(side adjacent x) • sin A = a/c, cosine A = b/c, & tangent A = a/b.
Re-Call • The reciprocal ratios are trigonometric ratios, too. They are outlined below. • cotangent x = 1/tan x = (adjacent side)/(opposite side) • secant x = 1/cos x = (hypotenuse)/(adjacent side) • cosecant x = 1/sin x = (hypotenuse)/(opposite side)
Definition of • Take any size of circle. Cis the Circumference, the distance around the outside. c d d is the Diameter.
Cis the Circumference, the distance around the outside. • d is the Diameter C 1 2 3 d C ynymwneud3gwaithd Cis about 3 times d
C 1 2 3 d C = 3.1415927 x d =3.1415927 (pi) This is true for any size of circle
Definition of radians s = r + s r
The picture below illustrates the relationship between the radius, and the central angle in radians. The formula is s = rθ where s represents the arc length, θ represents the central angle in radians and r is the length of the radius.
What is the value of the arc length s in the circle pictured below?
Calculate the measure of the arc length s in the circle pictured below?
Definition radians S = r = 2p radians r S = 2pr
Circumference • The circumference of a circle is the perimeter of the circle GylcheddCircumference
The diameter of a circle is a line across the circle which passes through the centre. • Radius • The radius of a circle is the distance from the centre of the circle to any point on the circumference. The radius is half the length of the diameter
Segment • A chord divides a circle into two segments: a minor segment and a major segment. Chord minor Segment bach Tant chord major Segment mawr
Tangent • A tangent is a line which touches the circumference of a circle at one point only and is parallel to the circumference at that point. • An arc is part of the circumference of a circle. • A sector is formed between 2 radii and the circumference arc tangent sector
Properties of a Circle • The angle in a semi-circle is always a right angle • If 2 chords are drawn from a point on the circumference of a circle to each end of a diameter the angle between the two chords is always a right angle.
The angle at the centre of a circle = twice the angle at the circumference If lines are drawn from each end of a chord to a point on the circumference of a circle and to the centre, the angle at the centre is twice the angle at the circumference.
Angles in the same segment are equal If two chords are drawn from a point on the circumference of a circle to each end of a third chord the intersecting angle is the same no matter where the point is providing the points are in the same segment of the circle.
Opposite angles in a cyclic quadrilateral are supplementary A cyclic quadrilateral is a quadrilateral whose vertices lie on the circumference of a circle. The opposite angles of a cyclic quadrilateral add up to 180
Tangents • A radius drawn from the point where a tangent touches a circle is perpendicular (at 90) to the tangent.
Tangents drawn to a circle from the same point outside the circle are equal in length. PA = PB • OP bisects angle APB A P O B
B is the centre of the circle. Find angles BPC, BCP, ABP and PAB. • BP = BC, BPC = BCP • (isosceles triangle) • BPC + BCP = 180 – 66 = 114 • BPC = BCP = 57 • ABP = 180 – 66 = 114 • (angles on a straight line = 180) • PAB = ½ × 66 = 33 • (angle at centre of a circle = twice that at the circumference) P 66 A C B
Calculate angles p, q and r. p + 85 = 180 (opposite angles in a cyclic quadrilateral) • p = 180 – 85 = 95 • q + 101 = 180 (opposite angles in a cyclic quadrilateral) • q = 180 – 101 = 79 • r + q = 180 (angles on a • straight line) • r = 180 – 79 = 101 r q p 85 101
3. Work out angles a, b, c and d. • a + 41 + 101 = 180 (angles in a triangle) • a = 180 – 41 – 101 = 38 • b = 101 (opposite angles) • d = 41 (angles in the same segment) • c = 38 • (angles in thesamesegment) a 41 101 b c d
4. Work out angles a, b and c. • c = 90 (angles in a semicircle) • a + 59 + 90 = 180 (angles in a triangle) • a = 180 – 59 – 90 = 31 • a + b = 90 (radius is • perpendicular to the tangent) • b = 90 – 31 = 59 c 59 b a
P • 5. Calculate angles XPY and OXY . • PX = PY PYX = PXY • (isosceles triangle) • PYX = 75 • PXO = 90 (radius is • perpendicular to the tangent) • OXY = 90 – 75 = 15 • XPY = 180 – 75 – 75 = 30 • (angles in a triangle) 75 X Y O
6. XTY is a tangent to the circle, centre O. P and Q are points on the circumference. OQ is parallel to PT. Angle QOT = 37. Find angles OPT and PTY. • OTP = 37 (alternate angles) • OP = OT OPT = OTP = 37(isosceles triangle) • OTY = 90 (radius is • perpendicular to the tangent) • PTY = OTY - OTP • PTY = 90 – 37 = 53 O 37 Q P T Y X
7. PTR is a tangent to the circle, centre O. The chord AB is parallel to PR. X is a point on the circumference. Angle ORT = 18. • Work out angle AXB. • OTR = 90 (radius is perpendicular to the tangent) • TOR = 180 – 90 – 18 = 72 (angles in a triangle) • TAB = ½ × 72 = 36 (angle at circumference = ½ angle at centre). • ATP = 36 (alternate angles) • ATO = 90 – 36 = 54 X O B A 18 R T P
OTR = 90, TOR = 72, TAB = 36, • ATP = 36, ATO = 54 • OT = OB OTB = OBT • (isosceles triangle) • OTB + OBT = 180 - TOR = 180 – 72 = 108 • OTB = ½ × 108 = 54 • ATB = ATO + OTB • ATB = 54 + 54 = 108 • AXB = 180 – 108 = 72 • (angles in a cyclic • quadrilateral) X O B A 18 R T P