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This week's lab involves a transformation lab overview and homework problem set 4 due in lab. Exam 2 preparation, group presentations, and review sessions are scheduled. Details on the Summer Scholar Program and a review of the last lecture on DNA and RNA are provided.
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Announcements Pick up lab overview for transformation lab this week. Homework-problem set 4- due in lab this week. 3. Look over Ch. 11, problems 4, 5, and 8 for exam 2. 4. Group B presentations are coming up 10/29, 30; start thinking of topics and deciding on sources. Group A did very well - pressure is on! 5. Review session in class Wednesday. Bring your questions! 6. Exam 2 next week: 10/17, 18, and 20. 15 multiple choice and 7 written (exam 1 had 18 multiple choice and 9 written). Exam is at CLAS testing center, available 3 days this time. Hours are 9-9 Thursdays, 9-5 Fridays, and 3-7 Sundays. Bring a pencil, bluebook, calculator. 7. Summer scholar program - research opportunity in summer, $2400 stipend. Need to find a faculty member to sponsor you. Often need to volunteer in the lab spring semester. Application includes a formal written proposal; deadline mid-Feb.; need 56 credits completed by start of summer and be returning next fall to CMU.
Review of Last Lecture Evidence that DNA is genetic material Structure of DNA/RNA: 5 different bases, 2 different sugars, phosphates History: the race to determine the structure of DNA was VERY competitive; 2 key pieces of data = Chargaff’s base compostion analysis and X-ray diffraction studies
Outline of Lecture 20 I. Structure of DNA II. Analytical analysis of nucleic acids III. Replication of DNA How is DNA organized? 1 single chain, 2 chains, 3 chains? How does the structure allow for replication, expression, storage and mutation?
I. The DNA Double Helix DNA structure • Double helical • major, minor grooves • right-handed • bases are 3.4 Å apart (10 Å = 1 nm) • 10 bases/turn • Complementary Base Pairing • through H bonds: A=T, GC • Antiparallel Strands • 5’ to 3’ • 3’ to 5’ Discussion of original paper in class Friday
Base-Pairing in DNA A=T GC
Structure of RNA Sugar: ribose, not 2-deoxyribose Bases: uracil, not thymine Organization: single-stranded, not double-stranded How is genetic information in DNA expressed? First step is transcribing RNA from DNA - single-stranded RNA is generated using DNA as a template
Reading DNA Strands Single strand of DNA: 5’-AGCATTCG-3’ 3’-TCGTAAGC-5’ Complementary strand of above, usually written 5’ to 3’: 5’-CGAATGCT-3’ Double-stranded fragment is written: 5’-AGCATTCG-3’ 3’-TCGTAAGC-5’
Learning Check The sequence of the dwarf gene in garden peas is as follows: 5’ - A G C T A C G T -3’ 3’ - T C G A T G C A -5’ Write the RNA sequence transcribed from the top strand of DNA, 5’- 3’.
II. Analytical analyses of nucleic acids Denaturation/Renaturation Determining the Tm allows for an estimate of the base composition of a DNA sample 1 2 Which DNA has higher GC content and why?
Nucleic Acid Hybridization Transcription of 1 strand of DNA 3 G G T T G G G C C A A C C C A C G C T T G C G A 2 1 U U U G C G C T T T G C G C A AA C G C G 3 Add RNA to denatured DNA; allow to hybridize Heat - denature A C G C T T G C G A G G T T G G G G G T T G G G C C A A C C C A C G C T 2 1 C C A A C C C T G C G A U U U G C G C Hybrid T T T G C G C A A A C G C G 3 A AA C G C G
What makes nucleic acids acidic? Base Pairing Rules
Points to know about DNA structure • Note how many hydrogen bonds are in the base pairing: • If 2, then the pair is AT • If 3, then the pair is GC • Recall that A and G are purines with 2 rings, while T and C are pyrimidines with 1 ring; also T has a CH3 group on its ring.
III. DNA Replication How is genetic information replicated accurately at each cell division? Could each strand of the DNA double helix act as a template for the complementary strand? At each cell division, 109 base pairs are replicated. If error rate is 10-6 , then 3000 errors/cell division - TOO many.
Meselson-Stahl Experiment DNA Labeling with 15N Subsequent Generations Labeled with 14N Cesium Chloride Gradient Banding
Expected Results From Conservative or Dispersive Reproduction If Conservative: Two bands, heavy and light, in 1st and 2nd generations If Dispersive, one smeary band in 1st and 2nd generations
Expected Results if Semiconservative These results were obtained. A related experiment was performed in plants (Fig. 12.5)
Bacterial DNA Replication begins at a Single Origin and Proceeds Bidirectionally Origin of Replication
DNA Polymerase I can Synthesize DNA • Arthur Kornberg et al. (1957) discovered the enzyme in E. coli • Requires template DNA strand, primer, MgCl2, and 4 dNTPs • Monomers added 5’ to 3’
DNA polymerases I, II and III • pol I • most abundant (400/cell) • RNA primer removal • pol II • unknown abundance • DNA repair? • pol III • low abundance (15/cell) • DNA replication
Problems of DNA Synthesis • Unwinding • Tension must be relieved • Priming • Antiparallel strands • RNA primer removal • Backbone joining • Proofreading
Steps of DNA Synthesis • Denaturation and Unwinding • Priming and Initiation • Continuous and Discontinuous Synthesis • Including Proofreading and Error Correction • Removal of Primer • Ligation of nicks in backbone
Steps of DNA Synthesis:Denaturation and Unwinding of DNA • DnaA, DnaB, DnaC proteins are helicases which bind origin and separate strands • Single-strand binding protein (SSBP) keeps strands apart • DNA gyrase, a type of DNA topoisomerase, cuts to relax supercoiling
Initiation of Synthesis • RNA Primase makes RNA primer on DNA template • DNA Polymerase III extends primer with DNA • DNA Polymerase I removes RNA primer, replaces with DNA
Proofreading occurs as polymerase moves along; if incorrect base pairing, base is removed and replaced.
Continuous and Discontinuous Synthesis • Continuous • on Leading Strand. • Discontinuous • on Lagging Strand • creates Okazaki • fragments. • DNA ligase joins • nicks in backbone.