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Problem # 1-6/5. mean core length = 52 cm length of air gap = 0.14 cm cross-sectional area = 18 cm 2 air gap flux density = 1.2 T Determine the voltage E. Use magnetization curve shown in Fig. 1.5. Problem #1-6/5. To determine the voltage E coil
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Problem # 1-6/5 mean core length = 52 cm length of air gap = 0.14 cm cross-sectional area = 18 cm2 air gap flux density = 1.2 T Determine the voltage E. Use magnetization curve shown in Fig. 1.5
Problem #1-6/5 • To determine the voltage Ecoil • Find the current in the coil, Icoil • Ecoil=IcoilRcoil • To determine the current Icoil • Calculate the total mmf • Calculate the coil current
Problem #1-6/5 continued • To determine F, calculate H
Problem #1-6/5 continued • To determine Hcore use Fig. 1.15 • Hcore={1.15 oersteds}{79.577 A-t/m/oersted} • Hcore=91.5 A-t/m • Then calculate Fcore • Fcore=Hcorelcore • Fcore={91.5 A-t/m}{0.52 m} • Fcore=47.58 A-t
Problem #1-6/5 continued • To determine Hgap • Hgap={1.2 Wb/m2}/{4πx10-7 Wb/A-t-m} • Hgap=955.4x103 A-t/m
Problem #1-6/5 continued • Calculating Fgap • Fgap=Hgaplgap • Fgap={955x103 A-t/m}{0.0014 m} • Fgap=1337 A-t • The total mmf • Ftotal=Fcore+Fgap • Ftotal={47.58+1337} A-t = 1384.58 A-t
Problem #1-6/5 continued • Calculate the coil current Icoil • Finally, the voltage