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Geometry Basketball . Reviewing Circles. Find the arc or angle. Solution . 55 +65 = 120 180-120= 60. Find the arc or angle. Solution . 55 º Vertical Angles are congruent!. Find the arc or angle. Solution . Semicircle + Arc NB 180 +55 = 235. Find the arc or angle. Solution .
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Geometry Basketball Reviewing Circles
Solution 55 +65 = 120 180-120=60
Solution 55º Vertical Angles are congruent!
Solution Semicircle + Arc NB 180 +55 =235
Solution Inscribed Angle is ½ of its intercepted arc <ABC = ½(84) =42
Solution Inscribed Angle is ½ its intercepted arc <ABC= ½ (arc AC) 65 = ½ (arc AC) 130 = arc AC
Solution When the lines intersect ON THE CIRCLE, the angle is ½ of the arc. 135= ½ (MLK) 270 = MLK
Solution When the lines intersect ON THE CIRCLE, the angle is ½ of the arc. m<1= ½ (260) m<1 = 130
Solution When the lines intersect IN THE CIRCLE, the angle is the sum of the arcs divided by 2. Wrong arcs125+105=230 360-230=130 Sum of correct arcs m<1=130/2 m<1 = 65
Solution When the lines intersect OUTSIDE THE CIRCLE, the angle is the bigger arc –smaller arc divided by 2. m<1= (122-64)/2 m<1 = 58/2 m<1 = 29
Solution When the lines intersect OUTSIDE THE CIRCLE, the angle is the bigger arc –smaller arc divided by 2. m<1= (135-55)/2 m<1 = 80/2 m<1 = 40
Solution When the lines intersect OUTSIDE THE CIRCLE, Outside segmet (whole segment) = Outside segment (whole segment) 8(x+8) = 9 (9) 8(x+8) = 9² 8x+64=81 8x=17 X=17/8
Solution When the lines intersect OUTSIDE THE CIRCLE, Outside segmet (whole segment) = Outside segment (whole segment) 5(3x+5) = 10 (10) 5(3x+5) = 10² 15x+25=100 15x=75 X=5
Solution Center : (-3,4) Radius: 6
Solution m<KMX = 75 Vertical Angles are Congruent!
Solution Semicircle = 180 90 +75 = 165 180 – 165 = 15
Solution Semicircle + Arc LY 180 + 75 255
Solution Inscribed Angle is ½ its intercepted arc m<TUV= ½ (arc TV) m<TUV = ½ (240) m<TUV = 120
Solution When the lines intersect ON THE CIRCLE, the angle is ½ of the arc. 53= ½ (arcAB) 106 = arc AB
Solution When the lines intersect IN THE CIRCLE, the angle is the sum of the arcs divided by 2. Use Semicircle 180 – 147 = 33 m<1= (67+33)/2 m<1=100/2 m<1=50
Solution When the lines intersect ON THE CIRCLE, the angle is ½ of the arc. Use full circle 360-150=210 m<1= ½ (210) m<1=105
Solution When the lines intersect OUTSIDE THE CIRCLE, the angle is the bigger arc –smaller arc divided by 2. Use full Circle 360-234 =126 m<1= (234-126)/2 m<1 = 108/2 m<1 = 54
Solution When the lines intersect IN THE CIRCLE, (part)(part) = (part)(part) (2x)(2x) = (5)(20) 4x²=100 x²=25 x= 5 or -5 (the lengths can’t be negative, so…) x=5
Solution When the lines intersect OUTSIDE THE CIRCLE, (part)(part) = (part)(part) (2x)(2x) = (5)(20) 4x²=100 x²=25 x= 5 or -5 (the lengths can’t be negative, so…) x=5
