140 likes | 333 Views
Problem #6. Using Winplot Animation on Secant Lines vs. Tangent Lines. Problem Description. Using the function , prove the slope of the secant line between x=1 and x=1+h gets closer to the slope of the tangent line as h approaches 0. Let’s start with graphing the equation:.
E N D
Problem #6 Using Winplot Animation on Secant Lines vs. Tangent Lines
Problem Description Using the function , prove the slope of the secant line between x=1 and x=1+h gets closer to the slope of the tangent line as h approaches 0.
Next, we shall find the tangent line: • To find the tangent line, you must first take the derivative of the equation • Now lets find the slope of the tangent line at point at x=1. • Now lets graph the equation of the tangent line using the slope formula • Find point of intersection of x=1 using the original equation. • Multiply the (x-1) with and add to both sides. • This gives us the equation of the tangent line. • . x • mat point (1,)
Now, we shall find the secant line: • h • Use the Secant Formula: Note: Remember F(x) is another term for y. • Enter into the formula above • Remember x=1. • Simplify • Multiply • Simplify. • Factor out an h. • Simplify
Equation of the Secant Line • Use the slope formula to graph the equation of the secant line. • Remember the known point is (1,).
Secant Lines • Let us begin by letting h=5 • Equation is: • Simplify:
Secant Lines • Let us begin by letting h=4 • Equation is: • Simplify:
Secant Lines • Let us begin by letting h=3 • Equation is: • Simplify: • 1
Secant Lines • Let us begin by letting h=2 • Equation is: • Simplify:
Secant Lines • Let us begin by letting h=1 • Equation is: • Simplify:
Secant Lines • Let us begin by letting h= • Equation is: • Simplify:
Summary • Using the previous slides we proved that • Has a tangent line at: • And the secant line between x=1 and x=1+h gets closer to the equation of the tangent line as h gets closer to 0. h=5 h=4 h=2 h=