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Geometric Optics Review. In the law of reflection the angle of incidence. is always greater than the angle of reflection is always less than the angle of reflection depends on the index of reflection and the angle of reflection is always equal to the angle of reflection.
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In the law of reflection the angle of incidence • is always greater than the angle of reflection • is always less than the angle of reflection • depends on the index of reflection and the angle of reflection • is always equal to the angle of reflection
The reason that you see a streak of light from the surface of a lake is that • The index of refraction of the water is greater than that of air • Light bends into the water and then gets scattered out • The surface of the water is rough • The surface of the water is smooth
The name for reflection from a smooth surface is • planar • specular • internal • diffuse • normal
The kind of reflection that allows us to see objects is • planar • specular • internal • diffuse • normal
In the above diagram, the angle of incidence is 20º • 20º • 50º • 70º • 90º
In the above diagram, the angle of reflection will be 20º • 20º • 50º • 70º • 90º
The angle of reflection can never be greater than • 0º • 45º • 90º • 180º
The angle of incidence can never be greater than • 0º • 45º • 90º • 180º
An image seen in a plane mirror is always • upright and real • upright and virtual • inverted and real • inverted and virtual
The magnification of an object in a plane mirror is • <1 • negative • >1 • 1
For a plane mirror, if the object is 10m in front of the mirror, then the image is • At the mirror • Less than 10m in front of the mirror • 10m in front of the mirror • Less than 10m behind the mirror • 10m behind the mirror • More than 10m behind the mirror
For a spherical mirror with radius, r, the focal length, f is given by: • f=2r • f=r • 2f=r
2 cm In the above diagram, the magnification is Image Object 3 cm • 0.5 • -0.5 • 1.0 • -1.0 • 1.5 • -1.5
2 cm In the above diagram, the image is Image Object 3 cm • virtual • imaginary • real
2 cm In the above diagram, the object distance is 4 cm Image Object 3 cm • 2 cm • 3 cm • -3 cm • 4 cm • 6 cm
2 cm In the above diagram, the image distance is 4 cm Image Object 3 cm • 2 cm • 3 cm • -3 cm • 4 cm • 6 cm
For mirror lenses, when the image distance is positive the image is • virtual • real
For glass lenses, when the image distance is positive the image is • virtual • real
If an image is upright, it must be • real • virtual
Do the light rays from a virtual image cross at the image location? • Yes • No
OF COURSE! YOU ONLY SEE THINGS WHEN THE IMAGE IS FOCUSED ON YOUR RETINA. Can the light rays from a virtual image be focused on your retina? • Yes • No
For the object above, which is a possible real image C Object B A D • A • B • C • D
For the object above, which is a possible virtual image C Object B A D • A • B • C • D
You want an image that is both real and upright. You need to use • A mirror lens • A glass lens • Neither will work
A The object and focal points are shown. Which is not a principle ray? B C D • A • B • C • D
For a spherical mirror, light that travels through the center of the sphere reflects • Parallel to the main axis • Through the focal point • Back on itself Focal Center
For a spherical mirror, light that travels through the focal point reflects • Parallel to the main axis • Through the focal point • Back on itself Center Focal
For a spherical mirror, light that travels parallel the the main axis reflects • Parallel to the main axis • Through the focal point • Back on itself Center Focal
The boy is looking in the mirror. This mirror is • Concave • Convex
The boy is looking in the mirror. This focal length is • Positive • Negative
The boy is looking in the lens. This lens is • Concave • Convex
The boy is looking in the lens. The focal length is • Positive • Negative
Snell’s Law Relates to • Reflection • Refraction • Diffraction • Reflection and Refraction
The index of refraction • can never be 1 • can never be greater than 1 • can never be less than 1
A high index of refraction corresponds to a • slow speed of light • high speed of light • neither. The speed of light never changes.
If a material has an index of refraction of 3.0, what is the speed of light in the material? • 1x108m/s • 2x108m/s • 3x108m/s • 6x108m/s • 9x108m/s
air A n=1.5 When going from lower index to higher index, the light bends TOWARD THE NORMAL B Light is incident from air to glass as shown. Which arrow shows the direction of the light in the glass? C D • A • B • C • D
n=1.5 A air When going from higher index to lower index, light always bends AWAY FROM THE NORMAL B Light is incident from glass to air as shown. Which arrow shows the direction of the light emerging from the glass? C D • A • B • C • D
Total internal reflection can occur when • light travels from air to water • light travels from water to air • either A or B • neither A or B
C A Light goes from air to glass as shown. Which arrow shows the path that it will leave the glass? B C D • A • B • C • D
refraction reflection refraction When light is incident on the glass, as shown • refraction occurs • reflection occurs • both A and B
An object is 1 cm from a glass lens. The image is 2 cm on the other side of the lens. The focal length of the lens is. • 1/3 cm • 2/3 cm • -2/3 cm • 1 cm • 3/2 cm • -3/2 cm
The critical angle is 49º for a particular type of glass. Light is incident from the glass to the air at an angle of 48º. Relative to the normal, the exit angle is • Close to 0º • Close to 42º • Close to 48º • Close to 90º
If the image distance is a positive number, the image is • real • virtual • upright
For a mirror lens, a positive focal length is • concave • convex
For a glass lens, a positive focal length is • concave • convex
air Light is incident from air to glass. The sin(θ1)=0.6 and thesin(θ2)=0.3. The index of refraction of the glass is θ2 θ1 • 1.0 • 1.5 • 2.0 • 2.5 • 3.0
Calcuations you should be able to make • Use the lens equation to solve for image, object, or focal length • Use the magnification formula • Use Snell’s law formula