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Molarity Problems

Molarity Problems. Molarity = mol/L Molarity = moles of solute / Liters of solution. Concentration. ~How much solute is present in a solution compared to the solvent. Molarity (M)- moles of solute per liter of solution. M = mol/L

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Molarity Problems

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  1. Molarity Problems Molarity = mol/L Molarity = moles of solute / Liters of solution

  2. Concentration • ~How much solute is present in a solution compared to the solvent. • Molarity (M)- moles of solute per liter of solution. M = mol/L • 2.1 M AgNO3 means 2.1 mol of AgNO3 for every one liter of solution

  3. Other measures of concentration

  4. How many moles of HCl are in 125 mL of 2.5 M HCl? Molarity problems .125 L of soln = .31 mol HCl

  5. Here we go • What concentration solution would be prepared if 39 g of Ba(OH)2 were mixed in a 450 mL solution? =.2276 mol Ba(OH)2 M = mol/L .2276 mol Ba(OH)2 .45 L of solution =.51 M Ba(OH)2

  6. More • For a lab in this chapter, I need to make .60 L of 3.0 M NaOH, what mass of NaOH did I need? • .6 L x 3.0 M NaOH = 1.8 mol NaOH • 1.8 mol NaOH x 39.998 g/mol • = 72 g NaOH

  7. Molarity Problems • A 0.24 M solution of Na2SO4 contains 0.36 moles of Na2SO4. How many liters were required to make this solution? 0.36 mol Na2SO4 1 L soln 0.24 mol = 1.5 L Na2SO4

  8. Getting tougher 2 2 • AgNO3 + BaCl2 AgCl + Ba(NO3)2 • Balance the equation. If 1.2 L of .50 M AgNO3 is reacted completely, what molarity solution of Ba(NO3)2 will be created if the volume increased to 1.5 L? 1.2 L x .5 M AgNO3 = .6 mol AgNO3 = .3 mol Ba(NO3)2 1.5 L = .20 M Ba(NO3)2

  9. Homework Problem • HNO3 + Zn  H2 + Zn(NO3)2 • If you have .45 L of 2.1 M HNO3 and you react it completely what volume of H2 gas will you produce at STP? • Solve for moles of H2, then use Avogadro’s law to get a volume at STP.

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