1 / 5

Задание

Задание. При каких действительных значениях x и y комплексные числа Z 2 =y i-x +3 и Z 1 =4i-2xy-xyi равны?. Решение. Решение. 2. 2. 2. 2. Z 1 =4i-2xy-xyi=-2xy+(4-xy)i Z 2 =y i-x +3=3-x +y i Z 1 =Z 2 , значит 3- x =-2xy x -2xy=3 4x -8xy=12

clare-ware
Download Presentation

Задание

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Задание При каких действительных значениях x и y комплексные числа Z2=y i-x +3 и Z1=4i-2xy-xyi равны? Решение

  2. Решение 2 2 2 2 Z1=4i-2xy-xyi=-2xy+(4-xy)i Z2=y i-x +3=3-x +y i Z1=Z2, значит 3-x =-2xy x -2xy=3 4x -8xy=12 y =4-xy y +xy=4 3y +3xy=12 4x -8xy=3y +3xy 4x -11xy-3y =0 y +xy=4 y +xy=4 4(x/y) -11x/y-3=0 y +xy=4 2 2 2 2 2 2 2 2 2 2 2 2 2 2 Дальше

  3. Из первого уравнения найдем x/y=3 или x/y=-1/4 Таким образом x/y=3 x/y=-1/4 y +xy=4 y +xy=4 x1=1 x2=-3x3= 3 /3 x4=- 3 /3 y1=1 y2=-1 y3=-4 3 /3 y4=4 3 /3 Ответ: (3;1); (-3;-1); ( 3 /3;-4 3 /3); (- 3 /3;4 3 /3); Или 2 2 И И Автор Выход

  4. Сделал Тукбаев Артур ученик 11 Б класса Школы №165 Выход

  5. The End

More Related