1 / 4

Composition of Functions

Composition of Functions. Chapter 1, Section 2 - Christina McInnis. Real World Application.

clarke
Download Presentation

Composition of Functions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Composition of Functions Chapter 1, Section 2 -Christina McInnis

  2. Real World Application • On February 8, a store will sell any item for $50 less than the listed price. On any day in February, the store will give a discount of 15% to any customer who can prove that he/she contributed to a local charity. • OK, let x be the listed price of an item in the store. • If P(x) is the price you will pay for an item on Feb. 8, then • P(x) = x - 50. • If D(x) is a price discounted at 15% , then, in February, the amount you will pay is • D(x) = 0.85x • You have two functions, P and D, which depend on the value of x, the listed price. If you don't know x, you can't calculate P(x) or D(x). And, note that if you do know x and "follow the rules," you get one value for P(x), and one value for D(x). P is a rule that says "take the listed price, than subtract $50." D is a rule that says "take the listed price, then take 85% of it." • P(x) = x - 50 and D(x) = 0.85x.

  3. If f(x)= x/2 -7 and g(x)=x+6 find [f o g] (x) note: [f o g] (x) = f(g(x)) Step 1 :substitute x+6 for g(x) f(g(x)) f(x+6) Step 2 :substitute g(x) for ever x value in f(x) f(x)= x/2 -7 x+6/2 -7 x/2 + 6/2 -7 x/2 + 3 – 7 x/2 -4 Answer: x/2 -4

  4. If f(x)= x/2 -7 and g(x)=x+6 find [g o f] (x) note: [g o f] (x) = g(f(x)) Step 1 :substitute x/2 -7 for f(x) g(f(x)) g(x/2 -7) Step 2 :substitute f(x) for ever x value in g(x) g(x)= x+6 x/2 -7 +6 x/2 -1 Answer: x/2 -1

More Related