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Check it out!. 2.2.2: Solving Systems of Linear Equations. Benito is a waiter. He earns a base salary of $1,500 a month, plus 20% of the price of the meals he serves. Write an equation to predict the amount of money Benito will earn if he serves $350 in meals.

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  1. Check it out! 2.2.2: Solving Systems of Linear Equations

  2. Benito is a waiter. He earns a base salary of $1,500 a month, plus 20% of the price of the meals he serves. Write an equation to predict the amount of money Benito will earn if he serves $350 in meals. Benito earned $1,650 in one month. What was the total price of the meals that Benito served? Create a graph to show the possible amount of money Benito could earn each month. 2.2.2: Solving Systems of Linear Equations

  3. Write an equation to predict the amount of money Benito will earn if he serves $350 in meals. Translate the verbal description of Benito’s pay into an algebraic equation. Let x represent the total cost of the meals Benito serves. Let y represent the amount of money Benito earns. Benito earns a base salary of $1,500, plus 20% of the price of the meals. 20% of the price of the meals is 0.20x. y = 1500 + 0.20x 2.2.2: Solving Systems of Linear Equations

  4. Benito served $350 in food. Substitute $350 for x and solve the equation for y, the amount of money Benito will earn. y= 1500 + 0.20x Original equation y= 1500 + 0.20(350) Substitute 350 for x. y= 1500 + 70 Simplify. y= 1570 Benito will earn $1,570 if he serves $350 worth of food. 2.2.2: Solving Systems of Linear Equations

  5. Benito earned $1,650 in one month. What was the total price of the meals that Benito served? Use your equation from part 1 to find the price of the meals Benito served. Substitute $1,650 for y, the total amount of money Benito earned. 1650 = 1500 + 0.20x 2.2.2: Solving Systems of Linear Equations

  6. Solve for x. Benito served $750 worth of meals. 2.2.2: Solving Systems of Linear Equations

  7. Create a graph to show the possible amount of money Benito could earn each month. The equation y = 1500 + 0.20x can be graphed using slope-intercept form. The slope of the equation is 0.20. The y-intercept is 1,500. 2.2.2: Solving Systems of Linear Equations

  8. 2.2.2: Solving Systems of Linear Equations

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