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Al13 EO3 TSW6 Linear Eq.

Al13 EO3 TSW6 Linear Eq. Ye Rin. Shelby. TSW 6. Linear Equation, Solving!!. Using a Table as a Check. Long. 400 students take Spanish and has been increasing 20 students per year. 98 students take German and has been decreasing 5 students per year.

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Al13 EO3 TSW6 Linear Eq.

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  1. Al13 EO3 TSW6 Linear Eq. Ye Rin Shelby TSW 6.LinearEquation, Solving!!

  2. Using a Table as a Check. Long • 400 students take Spanish and has been increasing 20 students per year. • 98 students take German and has been decreasing 5 students per year. • When will there be five times as many students taking Spanish as taking German? Making it Shorter

  3. verbal + label taking Spanish (400) + Increase (20) x Years (x) = Number taking German (98) Decrease (5) Years (x) 5 ( - x ) Algebraic 400+20x=5(98-5x) 400+20x=490-25x 400+20x+25x=490-25x+25x 400+45x=490 400-400+45x490-400 45x=90 X=2 Students taking Spanish will be five times than students taking German in two years!!

  4. Check Table 400+20=420 equal 98*5=490

  5. Using a Graph as a Check • A gazelle can run 73 ft per sec. For several minutes • A cheetah can run faster(88 ft per sec.) but can only sustain its top speed for about 20 sec. • How Far away from the cheetah does the gazelle need to stay for it to be safe?

  6. Solution Use a diagram. • If the gazelle is to far away for the cheetah to catch it within 20 seconds, the gazelle is probably safe. X Gazelle caught in 20 seconds If the gazelle is closer to the cheetah than x feet, the cheetah can catch the gazelle If the gazelle is farther away than x feet, the gazelle is in the safety zone

  7. … • To find the “Safety zone,” first find the starting distance for which the cheetah reaches the gazelle in 20 seconds. • To find the distance each animal runs in 20 seconds use the formula d=rt Distance Gazelle runs in 20 sec. Gazelle’s starting distance from cheetah Distance cheetah runs in 2o seconds Verbal Model + = Gazelle’s distance = 73 x 2o (feet) Gazelle’s starting distance from cheetah = x (feet) Cheetah’s distance = 88 x 20 (feet) 73 x 20 + x = 88 x 20 Labels Algebraic Model

  8. … • You find that x= 300, so the gazelle needs to stay more than 300 ft away from the cheetah to be safe. • Check~ Use a table or graph to check your answer. Why? • A graph helps you see relationships How? • First, make a table • Then, plot the points • Next, find and mark the points for every 5 sec.

  9. Thank you for watching!

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